2015-10-21 407 views
0

我得到我的程序从.csv文件读取并输出数据,但我不希望它输出第一行。我试过使用getline(data, line);stream.ignore (std::numeric_limits<std::streamsize>::max(), '\n');。尽管它没有跳过第一行,但最后两行打印两次并混合起来。C++跳过csv文件的第一行

string ID; 
string sentenceIn; 
string servedIn; 
int sentence; 
int served; 
string lastName; 
string firstName; 

vector<string> idNum; 
vector<string> sentenceLen; 
vector<string> servedTime; 
vector<string> lastNameIn; 
vector<string> firstNameIn; 


ifstream data("prisoner_data.csv"); 

if (data.is_open()) 
{ 
    cout << "File opened successfully." << endl << endl; 
    while (data.good()) // !someStream.eof() 
    { 
     getline(data, ID, ','); 
     cout << ID << " "; 
     idNum.push_back(ID); 

     getline(data, sentenceIn, ','); 
     cout << sentenceIn << " "; 
     sentenceLen.push_back(sentenceIn); 
     istringstream(sentenceIn) >> sentence; 

     getline(data, servedIn, ','); 
     cout << servedIn << " "; 
     servedTime.push_back(servedIn); 
     istringstream(servedIn) >> served; 

     getline(data, lastName, ','); 
     lastNameIn.push_back(lastName); 
     cout << lastName << " "; 

     getline(data, firstName, ','); 
     firstNameIn.push_back(firstName); 
     cout << firstName << " "; 
    } 
} 

我能做些什么,以跳过不搞乱了最后的第一行?

回答

1

while (data.good())很腥。你最终会“吃”多一行。见例如Why is iostream::eof inside a loop condition considered wrong?了解更多详情。通常你直接在while测试的getline的结果,就像

while(getline(data, line)){...} 

一个可能的解决方案是用while(getline(data, line)){...}到逐行读取文件中的行,然后用stringstream(line)和每行,再次与getline解析它,现在分开,。要跳过第一行,请先执行getline(data, line);,然后再执行while(getdata(data, line)){ /* process line */}。一个简单的例子如下:

#include <iostream> 
#include <string> 
#include <fstream> 
#include <sstream> 
#include <cstdlib> 

int main() 
{  
    std::ifstream data("prisoner_data.csv"); 
    if (!data.is_open()) 
    { 
     std::exit(EXIT_FAILURE); 
    } 
    std::string str; 
    std::getline(data, str); // skip the first line 
    while (std::getline(data, str)) 
    { 
     std::istringstream iss(str); 
     std::string token; 
     while (std::getline(iss, token, ',')) 
     { 
      // process each token 
      std::cout << token << " "; 
     } 
     std::cout << std::endl; 
    } 
} 
+0

谢谢你,这完美的作品。但是,我需要'句子'和'服务'是整数。我如何使用这种方式转换它们? – Andre

+0

@Andre您可以使用['std :: stoi'](http://en.cppreference.com/w/cpp/string/basic_string/stol)将字符串转换为整数。 – vsoftco