2014-02-09 58 views
0

有点卡在这里与相同的错误未定义的偏移量, 每个按钮点击如果去两个谷歌两个如果的,甚至是来自“名称”的值!= guy1它不跳过它,它做作业时,它会删除什么是应该,但它分配变量之前PHP错误与未定义的偏移量

<form action="deleteprog.php" method="post" > 
    <button type="submit" name="1000" id="1000" value="1000">DELETE</button> 
    <button type="submit" name="1001" id="1001" value="1001">DELETE2</button> 
</form> 



<?php 

mysql_connect("localhost", "root", "root") or die(mysql_error()); 
mysql_select_db("project") or die(mysql_error()); 


$guy1= 1000; 
$guy2= 1001; 
$name = htmlentities($_POST['1000']); 
echo $name; 
$name1 = htmlentities($_POST['1001']); 
echo $name1; 


if ($name == $guy1) 
{ 
    mysql_query("DELETE FROM progammers WHERE Sifra_zaposlenog= '1000'") 
    or die(mysql_error()); 
    echo "Member 1000 deleted"; 
} 
var_dump($name); 
if ($name1 == $guy2) 
{ 
    mysql_query("DELETE FROM progammers WHERE Sifra_zaposlenog= '1001'") 
    or die(mysql_error()); 
    echo "Member 1001 deleted"; 
} 
var_dump($name1); 


?> 
+1

看,阅读你的代码之前,应该清楚是什么做你想问 - 但你有问题是一个无法理解的大泥球。所以请更详细一些。 – carousel

回答

0
$name = (isset($_POST['1000'])) ? (int)$_POST['1000'] : null; 
$name1 = (isset($_POST['1001'])) ? (int)$_POST['1001'] : null; 
0

认沽检查配备了一个错误:

<?php 
if(isset($_POST)){ 
mysql_connect("localhost", "root", "root") or die(mysql_error()); 
mysql_select_db("project") or die(mysql_error()); 

    if(isset($_POST)){ 
     if (isset($_POST['1000']){ 
     $name1 = $_POST['1000']; 
     $guy1= 1000; 
     if ($name2 == $guy2){ 
      mysql_query("DELETE FROM progammers WHERE Sifra_zaposlenog= '1000'") 
      or die(mysql_error()); 
      echo "Member 1000 deleted"; 
     } 
     }elseif(isset($_POST['1001'])){ 
     $name2 = $_POST['1001']; 
     $guy2= 1001; 
     if ($name2 == $guy2){ 
      mysql_query("DELETE FROM progammers WHERE Sifra_zaposlenog= '1001'") 
      or die(mysql_error()); 
      echo "Member 1001 deleted"; 
     } 
     }else{ 
      echo "Member not set"; 
     } 
    mysql_close(); 
    } 
} 
?>