我正在尝试使用openpgp.js为JavaScript中的GnuPG加密文件编写示例解密器。JavaScript:使用openpgp.js解密GnuPG加密文件的内容
所以我试着它天真,甚至没有问,如果它甚至可能。我做了以下页面。
popup.html
<!doctype html>
<!--
-->
<html>
<head>
<title>Popup</title>
<script src="openpgp.js"></script>
<script src="popup.js"></script>
</head>
<body>
<p>Upload message: </p><input id="message" type="file"/><br>
<p>Upload secret key: </p><input id="secret" type="file"/><br>
<p>Secret key password: </p><input id="password" type="password"/><br><br>
<button id="decrypt">Decrypt</button>
<p id="output"></p>
<div id="loadingDiv"></div>
</body>
</html>
popup.js
var message = "";
var secret = "";
function readMessage (e) {
var file = e.target.files[0];
if (!file) {
message = "";
}
var reader = new FileReader();
reader.onload = function (e) {
message = e.target.result;
};
reader.readAsText (file);
}
function readSecret (e) {
var file = e.target.files[0];
if (!file) {
secret = "";
}
var reader = new FileReader();
reader.onload = function (e) {
secret = e.target.result;
};
reader.readAsText (file);
}
function loadScript(url, callback)
{
var head = document.getElementsByTagName ("head")[0];
var script = document.createElement ("script");
script.type = "text/javascript";
script.src = url;
script.onreadystatechange = callback;
script.onload = callback;
head.appendChild(script);
}
document.addEventListener ("DOMContentLoaded", function() {
document.getElementById ("message").addEventListener("change", readMessage, false);
document.getElementById ("secret").addEventListener("change", readSecret, false);
var gen = function() {
document.getElementById ("decrypt").addEventListener ("click", function() {
var output = document.getElementById ("output");
output.style.color = "black";
if (document.getElementById ("message").value == "") {
output.innerHTML = "No message provided";
output.style.color = "red";
}
else if (document.getElementById ("secret").value == "") {
output.innerHTML = "No secret key provided";
output.style.color = "red";
}
else if (document.getElementById ("password").value == "") {
output.innerHTML = "No password for secret key provided";
output.style.color = "red";
}
else {
var privateKey = openpgp.key.readArmored (secret).keys[0];
var isCorrect = privateKey.decrypt (document.getElementById ("password").value);
if (isCorrect) {
output.innerHTML = "";
output.style.color = "black";
var img = document.createElement ("img");
img.src = "loading.gif";
img.id = "loading";
document.getElementById ("loadingDiv").appendChild (img);
message = openpgp.message.readArmored (message);
openpgp.decryptMessage (privateKey, message).then (function (plaintext) {
output.innerHTML = plaintext;
}).catch (function(error) {
output.innerHTML = "Error while decrypting";
output.style.color = "red";
});
}
else {
output.innerHTML = "Incorrect password";
output.style.color = "red";
}
}
});
}
loadScript ("openpgp.js", gen);
});
openpgp.js给出message = openpgp.message.readArmored (message);
的Unknown ASCII armor type
错误。
那么有可能吗?如果是这样,我应该做一些不同的事情吗?
请更具体地在_where exactly_(哪条线)出现错误信息。猜测:您尝试加载用ASCII装甲编码的二进制信息。 –
@JensErat对不起,当我试图打开一条消息(编辑问题)时,你能否详细说明你的猜测,我并不完全了解它 –
OpenPGP标准中有两种“编码”,越多(空间)高效的二进制编码和ASCII铠装(类似于base64)。如果你的消息以'----- BEGIN PGP MESSAGE -----'开始,那么你使用的是ASCII装甲。我_guess_'readArmored'只会读取ASCII装甲消息。 –