tbl_group

（group_id，user_id，group_name，group_image，group_description，doi）MYSQL问题与连接查询

(9, 28, 'bbb', '1339660354imagesv.jpg', 'dfdsfsdf', '2012-06-14 13:22:34'), 
(11, 1, 'cccc', '', '', '2012-06-14 14:49:56'), 
(22, 1, '000', '', '', '2012-06-14 15:31:43');

tbl_groupnews

news_id，user_id，group_id，group_news，doi

(1, 1, 22, 'hi \n', '2012-06-14 16:20:36'), 
(2, 1, 22, 'hello', '2012-06-14 16:21:59'), 
(3, 1, 22, '1111', '2012-06-14 16:25:13'), 
(4, 1, 22, 'jj', '2012-06-14 16:34:41'), 
(5, 28, 9, 'hi', '2012-06-15 09:48:47');

`tbl_groupmembers`

groupmember_id，group_id，adder，member，doi

(1, 9, 28, 1, '2012-06-14 13:22:35'), 
(2, 9, 28, 66, '2012-06-14 13:22:35'), 
(4, 11, 1, 2, '2012-06-14 14:49:56'), 
(5, 11, 1, 28, '2012-06-14 14:49:56'), 
(6, 11, 1, 62, '2012-06-14 14:49:56'), 
(36, 22, 1, 28, '2012-06-14 16:15:41'), 
(37, 22, 1, 62, '2012-06-14 16:16:55'), 
(38, 22, 1, 66, '2012-06-14 16:18:35'), 
(39, 22, 1, 70, '2012-06-14 16:19:33');

我运行查询

SELECT tbl_groups.*, 
     COUNT (tbl_groupnews.news_id) AS cn1, 
     COUNT (tbl_groupmembers.group_id) AS cn2 
    FROM tbl_groups 
    LEFT JOIN tbl_groupnews ON tbl_groups.group_id = tbl_groupnews.group_id 
    LEFT JOIN tbl_groupmembers ON tbl_groupmembers.group_id = tbl_groups.group_id 
    WHERE (tbl_groups.user_id = 28 OR tbl_groupmembers.member = 28) 
GROUP BY tbl_groups.group_id

我的要求，我需要得到集团的所有值，新闻和合作的数量没有成员WHERE user_id = 28 or member id = 28。

任何人都可以帮助我找到解决方案吗？

来源

2012-06-15 Nisanth Kumar

哪里是tbl_groupnews是你的小组？ – jornare

更改了表名“tbl_groupnews” –

尝试这样的：

SELECT tbl_groups.*,   
COUNT (tbl_groupnews.news_id) AS cn1,   
COUNT (tbl_groupmembers.group_id) AS cn2  
FROM tbl_groups  
LEFT JOIN tbl_groupnews ON tbl_groups.group_id = tbl_groupnews.group_id 
AND tbl_groups.user_id = 28  
LEFT JOIN tbl_groupmembers ON tbl_groupmembers.group_id = tbl_groups.group_id 
AND tbl_groupmembers.MEMBER = 28 
GROUP BY tbl_groups.group_id

来源

2012-06-15 06:59:59 Rahul

嗨，如果我们从'tbl_groupmembers'中删除（36,22,1,28，'2012-06-14 16:15:41'），那么第三个组会再次出现。如果我们删除上面的行，组ID 22不会出现在我们的结果 –

如果选择从tbl_groups所有列，它们需要通过声明

SELECT tbl_groups.*,COUNT(distinct tbl_groupnews.news_id) as cn1, 
     COUNT(distinct tbl_groupmembers.group_id) as cn2 
    FROM tbl_groups 
    LEFT JOIN tbl_groupnews ON tbl_groups.group_id=tbl_groupnews.group_id 
    LEFT JOIN tbl_groupmembers ON tbl_groupmembers.group_id=tbl_groups.group_id 
    WHERE (tbl_groups.user_id = 28 or tbl_groupmembers.member=28) 
    GROUP BY tbl_groups.group_id,tbl_groups.user_id, tbl_groups.group_name, tbl_groups.group_image, tbl_groups.group_description, tbl_groups.doi

来源

2012-06-15 07:07:51 jornare

这个查询的计数结果是错误的 –

对不起，我没有时间测试它，但向计数添加'不同'应该做一些魔术：） – jornare

MYSQL问题与连接查询

tbl_group

tbl_groupnews

tbl_groupmembers

回答

相关问题

`tbl_groupmembers`