将二进制字符串转换为字符

Question

我已将某些字符转换为二进制。现在我想将它们转换回原始字符。任何人都可以告诉我该怎么做？

这是我的代码转换为二进制字符。

string = Integer.toBinaryString(c); 

其中c是char类型。所以，当我将char 'a'转换为二进制文件时，我得到了类似这样的内容 - 1101101

Answer 1

我不确定它在android中的工作原理，但是您是否试过简单的投射？

byte b = 90; //char Z 
char c = (char) b; 

Answer 2

使用Integer.parseInt(String s, int radix)有基数= 2（二进制）到String转化为int，然后投了int到char，像这样：

int parseInt = Integer.parseInt(your_binary_string, 2); 
char c = (char)parseInt; 

Answer 3

幸运的是，Java API提供一个将二进制字节翻译回原始字符的相当简单的方法。

String char = (char)Integer.parseInt(string, 2) 

该字符串是二进制代码的一个字节（8位）。 2表示我们目前处于2位。为此，您需要以8位部分填充上述二进制代码块。

但是，函数Integer.toBinaryString（C）并不总是在8块返回这意味着你需要确保你的原始输出是8

倍数它最终会寻找像这样：

public String encrypt(String message) { 
    //Creates array of all the characters in the message we want to convert to binary 
    char[] characters = message.toCharArray(); 
    String returnString = ""; 
    String preProcessed = ""; 

    for(int i = 0; i < characters.length; i++) { 
     //Converts the character to a binary string 
     preProcessed = Integer.toBinaryString((int)characters[i]); 
     //Adds enough zeros to the front of the string to make it a byte(length 8 bits) 
     String zerosToAdd = ""; 
     if(preProcessed.length() < 8) { 
      for(int j = 0; j < (8 - preProcessed.length()); j++) { 
       zerosToAdd += "0"; 
      } 
     } 
     returnString += zerosToAdd + preProcessed; 
    } 

    //Returns a string with a length that is a multiple of 8 
    return returnString; 
} 

//Converts a string message containing only 1s and 0s into ASCII plaintext 
public String decrypt(String message) { 
    //Check to make sure that the message is all 1s and 0s. 
    for(int i = 0; i < message.length(); i++) { 
     if(message.charAt(i) != '1' && message.charAt(i) != '0') { 
      return null; 
     } 
    } 

    //If the message does not have a length that is a multiple of 8, we can't decrypt it 
    if(message.length() % 8 != 0) { 
     return null; 
    } 

    //Splits the string into 8 bit segments with spaces in between 
    String returnString = ""; 
    String decrypt = ""; 
    for(int i = 0; i < message.length() - 7; i += 8) { 
     decrypt += message.substring(i, i + 8) + " "; 
    } 

    //Creates a string array with bytes that represent each of the characters in the message 
    String[] bytes = decrypt.split(" "); 
    for(int i = 0; i < bytes.length; i++) { 
     /Decrypts each character and adds it to the string to get the original message 
     returnString += (char)Integer.parseInt(bytes[i], 2); 
    } 

    return returnString; 
}