逆转'With Recursive'语句

Question

我有ff。查询显示董事的层次结构下，任何人：

WITH RECURSIVE emptree AS (
     SELECT e.win_id, 
      e.full_name, 
      e.current_sup_name, 
      e.sbu, 
      e.cost_center, 
      e.lob, 
      0 AS depth 
      FROM app_reports.vw_hiearchy e 
      WHERE e.win_id = xxxxxxx AND e.attrition_date IS NULL 
     UNION ALL 
     SELECT e.win_id, 
      e.full_name, 
      e.current_sup_name, 
      e.sbu, 
      e.cost_center, 
      e.lob, 
      t.depth + 1 AS depth 
      FROM app_reports.vw_hiearchy e 
      JOIN emptree t ON t.win_id = e.current_sup_win 
      WHERE e.attrition_date IS NULL 
     ) 
SELECT emptree.win_id, 
    emptree.full_name, 
    emptree.current_sup_name, 
    emptree.sbu, 
    emptree.cost_center, 
    emptree.lob, 
    emptree.depth 
    FROM emptree; 

，直到我请求增加另一个列（或以上），以显示谁是一个特定的监督员（技术上添加列动态监事它工作正常 - 如果可能的话，那从下往上显示所有主管）。我不确定是否需要颠倒这一点，才能从底层开始实际获取层次结构，并将其显示为current_sup_name_2，current_sup_name3等等。但我不知道如何。

在此先感谢您的任何建议。 :)

Answer 1

应该可以显示监事单场中完整的层次有一个小的修改现有的查询：

WITH RECURSIVE emptree AS (
     SELECT e.win_id, 
      e.full_name, 
      e.current_sup_name, 
      e.sbu, 
      e.cost_center, 
      e.lob, 
      0 AS depth 
      FROM app_reports.vw_hiearchy e 
      WHERE e.win_id = xxxxxxx AND e.attrition_date IS NULL 
     UNION ALL 
     SELECT e.win_id, 
      e.full_name, 
      concat_ws(',', e.current_sup_name, t.current_sup_name) current_sup_name, 
      e.sbu, 
      e.cost_center, 
      e.lob, 
      t.depth + 1 AS depth 
      FROM app_reports.vw_hiearchy e 
      JOIN emptree t ON t.win_id = e.current_sup_win 
      WHERE e.attrition_date IS NULL 
     ) 
SELECT emptree.win_id, 
    emptree.full_name, 
    emptree.current_sup_name, 
    emptree.sbu, 
    emptree.cost_center, 
    emptree.lob, 
    emptree.depth 
    FROM emptree;