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Question

使用XPath我曾问一个问题关于Traversing back to parent node in xpath

我得到预期的回应之前的节点，但是我有进一步发展一个更加怀疑。下面HTML：

<ul><li class="section">BROADCASTING</li> 
<ul> 
<li class="subsection"></li> 
<li class="circle"><a href="/article/95242-STATION_BREAK.php">STATION BREAK</a></li> 
<li class="circle"><a href="/article/98142-Labor_pains_hunger_pangs.php">Labor pains, hunger pangs</a></li> 
<li class="circle"><a href="/article/101509-Wake_up_call_for_Dream_Team.php">Wake-up call for Dream Team</a></li> 
<li class="circle"><a href="/article/136139-News_crew_turns_rescuer.php">News crew turns rescuer</a></li> 
<li class="circle"><a href="/article/136140-Chopper_safety_had_been_challenged.php">Chopper safety had been challenged</a></li> 
<li class="circle"><a href="/article/136142-Nielsen_adds_Dayton_.php">Nielsen adds Dayton..</a></li> 
<li class="circle"><a href="/article/136143-Mondale_watch.php">Mondale watch</a></li> 
<li class="circle"><a href="/article/136144-Those_70s_clearances.php">Those 70s clearances</a></li> 
<li class="circle"><a href="/article/136145-Oscar_goes_to_ABC.php">Oscar goes to ABC</a></li> 
<li class="circle"><a href="/article/136146-Hearst_Argyle_gives_a_green_light.php">Hearst-Argyle gives a green light</a></li> 
<li class="circle"><a href="/article/136147-Finding_Geena_Davis.php">Finding Geena Davis</a></li> 
<li class="circle"><a href="/article/136148-Syndication_Wrap_up.php">Syndication Wrap-up</a></li> 
<li class="circle"><a href="/article/136149-CBS_TV_news_pioneer_dies_at_86.php">CBS TV news pioneer dies at 86</a></li> 
<li class="circle"><a href="/article/136150-New_York_anchor_remembered.php">New York anchor remembered</a></li> 
<li class="circle"><a href="/article/136151-News_sharing_in_West_Virginia.php">News sharing in West Virginia</a></li> 
<li class="circle"><a href="/article/136152-News_dropping_in_Orlando.php">News dropping in Orlando</a></li> 
<li class="subsection">Null</li> 
<li class="circle"><a href="/article/136141-GET_WITH_THE_PROGRAM.php">GET WITH THE PROGRAM</a></li> 
<li class="subsection">PEOPLE'S CHOICE</li> 
<li class="circle"><a href="/article/97423-Syndication_as_branding.php">Syndication as branding</a></li> 
</ul> 
</ul> 

与@Alex的帮助，现在我可以得到所有的章节和小节。然后我想要这个小节里面的文章，我试了一下自己并收到了预期的输出，不过我现在的问题是在<li class="subsection">标签后面我们有个人<li class="circle">标签，里面包含anchor标签里的文章信息，现在由于class="circle"标签本身单个节点（不在class="subsection"节点内），我不能在特定的小节中获取文章，它将获取第一小节中的所有文章，然后在第二小节中它也从第三小节获取文章，只有在最后一个小节中才能正常工作，因为它没有更多的小节。

有谁能告诉我如何限制特定小节内的文章，我的意思是当它得到class="subsection"标签时，应该停止为该小节进一步提取文章，并开始获取另一个小节。

Answer 1

您可以使用类似：

//ul/ul[preceding::li[@class='section' and .=\"BROADCASTING\"]]/li[@class='subsection' and .=\"\"]/following::li[@class='circle' and following::li[@class='subsection' and .=\"Null\"]]/a

让所有<li class='subsection'></li>和<li class='subsection'>Null</li>之间的锚。要获得<li class='subsection'>Null</li>和<li class='subsection'>PEOPLE'S CHOICE</li>之间的链接，您需要在此处替换必要的值：li[@class='subsection' and .=\"{...}\"。

要获得最后一个小节下的锚点，下一个表达式就足够了： //ul/ul[preceding::li[@class='section' and .=\"BROADCASTING\"]]/li[@class='subsection' and .=\"PEOPLE'S CHOICE\"]/following::li[@class='circle']/a"。

我希望你已经发现了这个想法。