Python列表的理解失败，语法错误

Question

我在做练习3从http://cscircles.cemc.uwaterloo.ca/15b-python-pushups/，我做了代码的工作，但想知道是否有可能在更少的行中做到这一点？这里是我的解决方案：

los = [] # short for list of strings 
while True: 
    s = input() 
    if s == '###': break 
    los += s.lower().split() # making a list of lower case words from the input  sentences 
test = [] 
for x in los: 
    test += str(los.count(x)) # made a new list of the frequency of each word 
a = test.index(max(test)) # variable a provides the location of them most frequent word 
print (los[a]) # we know the position of the most frequent string, so find it in los. 
# a is not needed but it looks neater 

所以这部分尤其是我不是很满意：

for x in los: 
     test += str(los.count(x)) 

我要重新写，如：

test += str(list.count(x)) for x in los 

但告诉我无效的语法..所有提示？

Answer 1

我想你想的语法是：

# No need for test = [] 
    test = [str(list.count(x)) for x in los]