中给出请有人可以告诉我这段代码有什么问题,它显示此错误---------> 警告:mysql_num_rows()期望参数1在第62行上的/home/ocwnewco/public_html/user/rejectedcase.php中给出了布尔值,第62行显示了这个-------> $ ocwConnections = mysql_num_rows($ result);数据库mysql_num_rows()期望参数1是资源,布尔在
rejectedcase.php
<?php
require_once(ROOT_PATH.'DBconnect.php');
?>
<?php
/**
*get count of Reject
*
**/
function totalReject($zone,$Reject) {
$result = mysql_query("SELECT * FROM ocwconnections WHERE ZoneID = '$zone' AND RejectID = '$Reject'");
$ocwConnections = mysql_num_rows($result);
return $ocwConnections;
}
$ocwConnections = mysql_fetch_array(mysql_query("SELECT * FROM ocwconnections"));
$resultZone = mysql_query("SELECT * FROM `connection_zone` WHERE `Zone` <> 'All' ");
$resultReject = mysql_query("SELECT * FROM `connection_Reject` WHERE `Reject` <> 'All'");
?>
<?php
?>
<table border="1">
<tr>
<th class="tbhed">Zone</th>
<?php
$Reject = array();
while($connectioReject = mysql_fetch_array($resultReject)) {
echo "<th class=tbhed>".$connectioReject['Reject']."</th>";
$Reject[] = $connectioReject['RejectID'];
}
?>
<th class="tbhed">Total</th>
<th class="tbhed">Percentage</th>
</tr>
<?php
$arr = array();
while($connectioZone = mysql_fetch_array($resultZone)) {
?>
<tr>
<th><?php echo $connectioZone['Zone']; ?></th>
<?php
foreach($Reject as $value){
$arr[$connectioZone['ZoneID']][$value] = totalReject($connectioZone['ZoneID'],$value);
echo "<td>".totalReject($connectioZone['ZoneID'],$value)."</td>";
}
?>
<td><?php
$total = 0;
foreach($arr[$connectioZone['ZoneID']] as $value){
$total = $value + $total;
}
echo $total;
?>
</td>
<td><?php
foreach($arr[$connectioZone['ZoneID']] as $key => $val){
if($key == 2){
$complete = $val;
}
}
@$per = $complete * 100/$total;
if(!$per){
echo $per = 0;
}
else {
echo $per;
}
?>
% </td>
</tr>
<?php
}
?>
</table>
使用或从句前的mysql_query( “查询”)检查您的查询或死亡( “查询!”);这会让你知道查询是否正在执行。 – rohitr
请参阅[此答案](http://stackoverflow.com/a/11674313/250259)了解如何解决此问题。 –