嗨我是新来的java和我在分数计算器上工作,我无法弄清楚如何让计算器减少简单分数和添加混合分数。 示例: 缩减:1/2 + -5/6 = -1/3
混合分数:4_15/16 + -3_11/16 = 1_1/4 编辑:对于混合分数,我尝试从分子中减去num> den的分母以获取整个和剩余部分,并将其返回并打印出来,但不打印任何内容。馏分计算器添加
import java.util.Scanner;
public class Fraction {
public static void main(String[] args) {
System.out.println("Enter an Expression or quit:");
Scanner input = new Scanner(System.in);
String text = input.nextLine();
while (!text.equals("quit")){
String frac1 = text.substring(0,text.indexOf(" "));
String oper = text.substring((text.indexOf(" "))+1,(text.indexOf(" "))+2);
String frac2 = text.substring((text.indexOf(" "))+3);
int fn1 = num(frac1); //frac1 numerator
int fd1 = den(frac1); //frac1 denominator
int fn2 = num(frac2); //frac2 numerator
int fd2 = den(frac2); //frac2 denominator
if (oper.equals("+")){
int sumfinalnum = add(fn1, fd1, fn2, fd2);
if (fd1 == 1 && fd2 == 1){
System.out.println(sumfinalnum);
}
else if ((fn1 + fn2)==0){
System.out.println("0");
}
else if (fd1 == fd2){
if (sumfinalnum>fd1){
System.out.println(extractWholePart(sumfinalnum,fd1)+"_"+extractNumPart(sumfinalnum,fd1)+"/"+fd1);
}
else{
System.out.println(sumfinalnum+"/"+fd1);
}
}
else if (!(fd1 == fd2)){
System.out.println(sumfinalnum+"/"+(fd1*fd2));
}
System.out.println("Enter an Expression or quit:");
text = input.nextLine();
}
}
}
public static int num(String input){
if (input.contains("_")){ //mixed to improper
String a = input.substring(0,input.indexOf("_"));
String b = input.substring((input.indexOf("_"))+1,input.indexOf("/"));
String c = input.substring((input.indexOf("/"))+1);
int a1 = Integer.parseInt(a);
int b1 = Integer.parseInt(b);
int c1 = Integer.parseInt(c);
int d = a1*c1;
int e = d+b1;
return e;
}
else if (!input.contains("/")){
int input1 = Integer.parseInt(input);
return input1;
}
else {
String strnum1 = input.substring(0,input.indexOf("/"));
int num1 = Integer.parseInt(strnum1);
return num1;
}
}
public static int den(String input){
if(!input.contains("/")) { //whole
return 1;
}
String strnum2 = input.substring((input.indexOf("/"))+1);
int num2 = Integer.parseInt(strnum2);
return num2;
}
public static int add(int fn1,int fd1,int fn2,int fd2){
if (fd1 == fd2){ //matching denominator
int numadd = fn1 + fn2;
return numadd;
}
else if (fd1 == 1 && fd2 == 1){ //whole numbers no denom
int sum = fn1 + fn2;
return sum;
}
else if (!(fd1 == fd2)){ //different denominator***
int dencomadd = fd1*fd2;
int gcd1 = dencomadd/fd1;
int gcd2 = dencomadd/fd2;
int comf1num = fn1*gcd1;
int comf2num = fn2*gcd2;
int total = comf1num+comf2num;
return total;
}
else{
return 0;
}
}
public static int extractWholePart(int finalnum, int finalden){
int whole = 0;
while (finalnum > finalden){
whole++;
}
return whole;
}
public static int extractNumPart(int finalnum, int finalden){
while (finalnum > finalden){
finalnum -= finalden;
}
return finalnum;
}
}
为了减少一小部分:如果结果是A/B,则找到G ='的Math.abs最大公约数(A)'和B.然后减少除以A和B的分数。所以如果A = -4和B = 12,G将是4,然后你将A和B除以4得到-1/3。如果您不知道如何找到最大公约数,请在维基百科中查找“欧几里德算法”。 – ajb 2014-11-24 23:00:03