2013-09-21 24 views
1

我从JSON字符串生成JAVA对象。但是我在迭代列表项时遇到了问题。这个JSON是一个嵌套数组。这是我的Java代码如何迭代由GSON制作的JAVA对象列表

response.setContentType("text/html"); 
    PrintWriter out = response.getWriter(); 

    nString xr = request.getParameter("JSONString"); 
    Gson gson = new Gson(); 
    java.lang.reflect.Type type = new TypeToken<List<EmployeeJSONObj>>(){}.getType(); 
    List<EmployeeJSONObj>l = gson.fromJson(xr, type); 
    List<EmployeeJSONObj>l1 = l.get(0).getChild(); 

for(int i=0;i<l1.size();i++) 
      { 
       out.println("Name: "+l1.get(i).getName()+"<br/>"); 
      } 

和我的Java自定义类是

public class EmployeeJSONObj { 
    private String name; 
    private List<EmployeeJSONObj> children = new LinkedList<>(); 
    EmployeeJSONObj() 
    { 

    } 
    public String getName() 
    { 
     return name; 
    } 

    public List<EmployeeJSONObj> getChild() 
    { 
     return children; 
    } 

    public String toString() { 
     return "name: " + name + ", children = " + children; 
    } 

} 

和JSON字符串来了来回HTML隐藏字段,这里是我的JSON字符串

String str = "[{" + 
      " \"name\": \"3214657890RootSAPSSE\"," + 
      " \"children\": [{" + 
      "  \"name\": \"672BENIAMEEN .Sales Base Market SectionCustomer Representative\"," + 
      "  \"children\": [{" + 
      "   \"name\": \"672BENIAMEEN .Sales Base Market SectionPeão\"," + 
      "   \"children\": [{" + 
      "    \"name\": \"910MAZHAR .Sales Base Market SectionCustomer Representative\"," + 
      "    \"children\": [{" + 
      "     \"name\": \"910MAZHAR .Sales Base Market SectionPeão\"," + 
      "     \"children\": [{" + 
      "      \"name\": \"713NOSHERWAN .Sales Sargodha SectionCustomer Representative\"," + 
      "      \"children\": [{" + 
      "       \"name\": \"713NOSHERWAN .Sales Sargodha SectionPeão\"" + 
      "      }," + 
      "      {" + 
      "       \"name\": \"1161SAQLAIN .Sales Toba Taik Singh SecPeão\"" + 
      "      }]" + 
      "     }]" + 
      "    }]" + 
      "   }]" + 
      "  }," + 
      "  {" + 
      "   \"name\": \"1161SAQLAIN .Sales Toba Taik Singh SecCustomer Representative\"," + 
      "   \"children\": [{" + 
      "    \"name\": \"1179SHAMOON .Administration SectionDriver (R)\"" + 
      "   }]" + 
      "  }]" + 
      " }," + 
      " {" + 
      "  \"name\": \"1179SHAMOON .Farooq Khan TrustDriver (D)\"" + 
      " }]" + 
      "}]"; 

当我运行上面的代码只显示在关卡的儿童中。但是我想迭代整个对象列表。

有什么想法?请帮忙。

回答

0

使用递归超过EmployeeJSONObj

public class Help { 

public static void main(String args[]) { 
    String str = "[{" + 
      " \"name\": \"3214657890RootSAPSSE\"," + 
      " \"children\": [{" + 
      "  \"name\": \"672BENIAMEEN .Sales Base Market SectionCustomer Representative\"," + 
      "  \"children\": [{" + 
      "   \"name\": \"672BENIAMEEN .Sales Base Market SectionPeão\"," + 
      "   \"children\": [{" + 
      "    \"name\": \"910MAZHAR .Sales Base Market SectionCustomer Representative\"," + 
      "    \"children\": [{" + 
      "     \"name\": \"910MAZHAR .Sales Base Market SectionPeão\"," + 
      "     \"children\": [{" + 
      "      \"name\": \"713NOSHERWAN .Sales Sargodha SectionCustomer Representative\"," + 
      "      \"children\": [{" + 
      "       \"name\": \"713NOSHERWAN .Sales Sargodha SectionPeão\"" + 
      "      }," + 
      "      {" + 
      "       \"name\": \"1161SAQLAIN .Sales Toba Taik Singh SecPeão\"" + 
      "      }]" + 
      "     }]" + 
      "    }]" + 
      "   }]" + 
      "  }," + 
      "  {" + 
      "   \"name\": \"1161SAQLAIN .Sales Toba Taik Singh SecCustomer Representative\"," + 
      "   \"children\": [{" + 
      "    \"name\": \"1179SHAMOON .Administration SectionDriver (R)\"" + 
      "   }]" + 
      "  }]" + 
      " }," + 
      " {" + 
      "  \"name\": \"1179SHAMOON .Farooq Khan TrustDriver (D)\"" + 
      " }]" + 
      "}]"; 

    System.out.println(str); 

    Gson gson = new Gson(); 
    Type type = new TypeToken<List<Employees>>(){}.getType(); 
    List<Employees >l = gson.fromJson(str, type); 
    System.out.println(l); 

    iterateOverEmployee(l); 
} 

private static void iterateOverEmployee(List<EmployeeJSONObj> l) { 
    for(EmployeeJSONObj emp: l){ 

     if(emp.getChildren() != null){ 

      for(int i=0;i<emp.getChildren().size();i++) 
      { 
       System.out.println("Name: "+emp.getChildren().get(i).getName()+"<br/>"); 
      } 

      iterateOverEmployee(emp.getChildren()); 
     }   
    } 
} 

儿跑EmployeeJSONObj

public static class EmployeeJSONObj { 
    private String name; 
    private List<EmployeeJSONObj> children; 


    public String getName() 
    { 
     return name; 
    } 

    public String toString() { 
     return "name: " + name + ", children = " + children; 
    } 
    public List<EmployeeJSONObj> getChildren() { 
     return children; 
    } 
    public void setChildren(List<EmployeeJSONObj> children) { 
     this.children = children; 
    } 

} 

输出:

Name: 672BENIAMEEN .Sales Base Market SectionCustomer Representative<br/> 
Name: 1179SHAMOON .Farooq Khan TrustDriver (D)<br/> 
Name: 672BENIAMEEN .Sales Base Market SectionPeão<br/> 
Name: 1161SAQLAIN .Sales Toba Taik Singh SecCustomer Representative<br/> 
Name: 910MAZHAR .Sales Base Market SectionCustomer Representative<br/> 
Name: 910MAZHAR .Sales Base Market SectionPeão<br/> 
Name: 713NOSHERWAN .Sales Sargodha SectionCustomer Representative<br/> 
Name: 713NOSHERWAN .Sales Sargodha SectionPeão<br/> 
Name: 1161SAQLAIN .Sales Toba Taik Singh SecPeão<br/> 
Name: 1179SHAMOON .Administration SectionDriver (R)<br/> 

作为一个侧面说明

使用Notepad ++或其他工具来格式化Json字符串。通过这种方式,你可以避免一些错误

+0

这很好,但当我更改JSON字符串,就像我添加更多的孩子,并使其更加嵌套时,它再次只显示我2个孩子。我的json是动态生成的,可以达到用户想要的尽可能多的孩子。 – user2777070

+0

你可以发布更多的孩子json吗?从你的代码'Employees emp = l.get(0);'我们只使用第一个孩子,所以... –

+0

我改变了我的代码,现在试试,运行所有的孩子 –