Android的onClick方法ImageSwitcher

Question

基本上我有一个数组，其中有2个图像，好像现在，但最终会有更多。 每隔几秒从阵列切换器获取图像。我坚持使用onClick方法。用户点击该图像时的最终目标新的Activity类打开。每个图像都有自己的Activity类，所以当用户点击它时，它应该被引导到那个特定的类。

我也得到了一些帮助，昨天

public void onClick(View v) { 
     Intent n = null; 
     int id = v.getId(); 
     switch (id){ 
      case R.id.someId: 
       n = new Intent(getActivity(), FragMent1.class); 
       break; 
      case R.id.someOtherId: 
       n = new Intent(getActivity(), FragMent2.class); 
       break; 
     } 

我可以设置第一个case语句是“R.id.textSwitcher”，但第二个是问题。因为我想要的图像在一个地方会以动画方式，新R.id ...意味着新的位置也有新的“mSwitcher1.setOnClickListener（新View.OnClickListener（）”

public class Animation extends Fragment implements AnimationListener { 

    public HomeAnimation(){} 
    private static boolean flag = false; 
    Animation anim; 
    private Handler handler; 
    public ImageSwitcher mSwitcher,mSwitcher1; 

    int textToShow[] = {R.drawable.dabangg, R.drawable.car }; 

    int messageCount = textToShow.length; 
    int currentIndex = -1; 
    @Override 
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { 
     View v = inflater.inflate(R.layout.imgswitch, container, false); 
     mSwitcher = (ImageSwitcher) v.findViewById(R.id.imageSwitcher1); 
     mSwitcher.setFactory(mFactory); 
     anim = AnimationUtils.loadAnimation(getActivity(),R.anim.fade_in); 

     mSwitcher.setOnClickListener(new View.OnClickListener() { 
      public void onClick(View v) { 
       Intent n = null; 
       int id = v.getId(); 
       // Fragment fragment = null; 
       //Bundle args = new Bundle(); 
       switch (v.getId()){ 
       case 0: 
        n = new Intent(getActivity(), Fragment1.class); 
        getActivity().startActivity(n); 
        break; 
       case 1: 
        n = new Intent(getActivity(), Fragment2.class); 
        getActivity().startActivity(n); 
        break; 
       } 
      } 
     }); 
     // set animation listener 
     anim.setAnimationListener(this); 
     return v;  
    } 

public void updateTextView() { 

    int maxIndex = textToShow.length; 
    Random random = new Random(); 
    int generatedIndex = random.nextInt(maxIndex); 
    mSwitcher.setImageResource(textToShow[generatedIndex]); 

}

这里是一个什么我在更新的情况下，如果有人需要它

public void updateTextView() { 

     int maxIndex = textToShow.length; 
     Random random = new Random(); 
     final int generatedIndex = random.nextInt(maxIndex); 
     mSwitcher.setImageResource(textToShow[generatedIndex]); 
     mSwitcher.setOnClickListener(new View.OnClickListener() { 
      public void onClick(View v) { 
       Intent n = null; 

       switch(generatedIndex){ 
       case 0: 
        n = new Intent(getActivity(), Fragment1.class); 
         getActivity().startActivity(n); 
         break; 

       case 1: 
         n = new Intent(getActivity(), Fragment2.class); 
         getActivity().startActivity(n); 
         break; 
       case 2: 
         n = new Intent(getActivity(), Fragment3.class); 
         getActivity().startActivity(n); 
         break; 

       } 
      } 
     }); 

Answer 1

我现在没有时间来测试这个权利，我不能完全肯定我理解您的问题，但试试这个，看看它是否是你想要的我会在代码

mSwitcher.setOnClickListener(new View.OnClickListener() { 
     public void onClick(View v) { 
      Intent n = null; 
      int id = v.getId(); 
      // Fragment fragment = null; 
      //Bundle args = new Bundle(); 
      switch (v.getId()){ 
      case 0: 
       /* 
       below should give you the index for the displayed image 
       you can compare this to the ids in your array using the index 
       */ 
       if (v.getDisplayedChild() == 0) { // if 1st image in array do this 
        n = new Intent(getActivity(), Fragment1.class); 
        getActivity().startActivity(n); 
       } 
       if (v.getDisplayedChild() == 1) { // if 2nd image in array do this 
        n = new Intent(getActivity(), Fragment2.class); 
        getActivity().startActivity(n); 
       } 
       break;