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这里是我的代码线程在窗口
public partial class MainWindow : Window
{
Thread ProgressThread;
Window w;
public MainWindow()
{
InitializeComponent();
}
private void button1_Click(object sender, RoutedEventArgs e)
{
ProgressThread = new Thread(() =>
{
w = new Window();
RoundProgressBar objprogress=new RoundProgressBar();
w = new Window();
w.Margin = new Thickness(0, 0, 50, 0);
w.WindowState = WindowState.Normal;
w.WindowStartupLocation = WindowStartupLocation.CenterOwner;
w.Height = 80;
w.Width = 80;
w.ResizeMode = ResizeMode.NoResize;
w.AllowsTransparency = true;
w.WindowStyle = WindowStyle.None;
RoundProgressBar Progress = new RoundProgressBar();
w.Content = objprogress;
w.ShowInTaskbar = false;
w.ShowDialog();
w.Content = Progress;
w.ShowInTaskbar = false;
w.ShowDialog();
w.Closed += (sender2, e2) =>
w.Dispatcher.InvokeShutdown();
System.Windows.Threading.Dispatcher.Run();
});
ProgressThread.SetApartmentState(ApartmentState.STA);
ProgressThread.Start();
}
}
当我按一下按钮线程开始在屏幕中间的进度条。当我改变主屏幕,在不改变progree栏窗口。
我想显示那个窗口的中间进度条。如果我搬到任何地方。
w.Owner = this;
我知道这个代码的帮助下,这将工作perfect.but我在线程正在工作,所以这种错误是发生
“因为不同的线程拥有它调用线程不能访问此对象”请帮我解决这个问题