如何解决在where子句

Question

如何解决SQL查询的SQL查询的WHERE子句，我有数据

TranID HotelID FacilityID 
7  1  4 
9  1  8 
12  2  4 
13  2  8 
19  9  4 
229 2  8 
244 74  8 

我希望像这样显示，在酒店ID将是同为不同FacilityID

TranID HotelID FacilityID 
7  1  4 
9  1  8 
12  2  4 
13  2  8 

所以请帮助我在此先感谢

Answer 1

Select * from [My-table] 
where HotelID in (1, 2) 

Answer 2

SELECT * FROM [YourTable] 
WHERE TranID IN (7,9,12,13) 

Answer 3

SELECT * from table where HotelID IN (1,2) 

Answer 4

检查：

SELECT t1.* 
    FROM tableHotel t1 
    WHERE EXISTS 
    (
    SELECT 1 FROM tableHotel t2 
    WHERE t2.HotelID= t1.HotelID 
    AND t2.FacilityID <> t1.FacilityID 
    ) 

Answer 5

它解决了U上要选择什么样的标准 http://sqlfiddle.com/#!2/82849/46

SELECT DISTINCT h.*,c.CITY 
    FROM MST_FacilityTrans t1 
    INNER JOIN MST_HOTEL h on h.HotelID=t1.HotelID 
    INNER JOIN MST_City c on h.CityID=c.CityID 
    WHERE EXISTS 
    (
    SELECT 1 FROM MST_FacilityTrans t2 
    WHERE t2.HotelID= t1.HotelID 
    AND t2.FacilityID <> t1.FacilityID 
    )