查找字符的索引在字符串

Question

我有一个字符串NSString *Original=@"88) 12-sep-2012";或Original=@"8) blablabla";

我想只打印前的字符“）”，因此如何找到字符的索引“）”。或者我该怎么做？

在此先感谢。

Answer 1

NSString *str = [[yourString componentsSeparatedByString:@")"] objectAtIndex:0]; 

Answer 2

您能给我们下面的代码，看看之前字符 “）”

// this would split the string into values which would be stored in an array 
    NSArray *splitStringArray = [yourString componentsSeparatedByString:@")"]; 
    // this would display the characters before the character ")" 
    NSLog(@"%@", [splitStringArray objectAtIndex:0]); 

Answer 3

NSUInteger index = [Original rangeOfString:@")"]; 

NSString *result = [Original substringWithRange:NSMakeRange(0, index)]; 

Answer 4

U可以找到人物的指数 “）” 是这样的：

NSString *Original=@"88) 12-sep-2012"; 
NSRange range = [Original rangeOfString:@")"]; 
if(range.location != NSNotFound) 
{ 
NSString *result = [Original substringWithRange:NSMakeRange(0, range.location)]; 
} 

Answer 5

另一个解决方案：

NSString *Original=@"88) 12-sep-2012"; 
NSRange range = [Original rangeOfString:@")"]; 
NSString *result = Original; 

if (range.location != NSNotFound) 
{ 
    result = [Original substringToIndex:range.location]; 
} 

NSLog(@"Result: %@", result); 

Answer 6

尝试下面的代码以获取特定字符的索引中的字符串： -

NSString *string = @"88) 12-sep-2012"; 
NSCharacterSet *charSet = [NSCharacterSet characterSetWithCharactersInString:@")"]; 
NSRange range = [string rangeOfCharacterFromSet:charSet]; 

if (range.location == NSNotFound) 
{ 
    // ... oops 
} 
else { 
    NSLog(@"---%d", range.location); 
    // range.location is the index of character) 
} 

，并获得）字符使用前字符串这样的： -

NSString *str = [[string componentsSeparatedByString:@")"] objectAtIndex:0];