JSON解析PHP的问题

Question

我有这样的JSON响应

{"success":true,"results":[{"response":["random1"],"id":"6566","Limit":1},{"response":["random2"],"id":"6563","Limit":1},{"response":["random3"],"id":"6568","Limit":1}]} 

所有我需要的是从响应提取random1，random2，随机，3所以最终的结果将是：

• random1
• random2
• random3

我有此脚本

$jsonData = file_get_contents("json"); 

$json = json_decode($jsonData,true); 

foreach($json["results"][0]["response"] as $data) { 
{ 
    echo json_encode($data); 

} 
} 

但是，这将只提取

• random1

如果我改变[0]在[1]将提取random2和[2] random3 如何，我可以得到random1，random2，随机3，一次回应？所以最终的回音是：

• random1
• random2
• random3

预先感谢您，任何帮助，将不胜感激！

Answer 1

循环在你$json['result']你做什么只接收第一指标0具有random1作为其response值

$json = '{"success":true,"results":[{"response":["random1"],"id":"6566","Limit":1},{"response":["random2"],"id":"6563","Limit":1},{"response":["random3"],"id":"6568","Limit":1}]}'; 
$json = json_decode($json,true); 

foreach($json["results"] as $data) { 
    echo $data['response'][0]."\n"; 
} 

试试吧here

---

更新

如果你想过滤让我们说random1然后做这样的

$json = json_decode($json,true); 
$filter = array("random1"); //You can add items to filter 
$result = array(); 
foreach($json["results"] as $data) { 
    if(!in_array($data['response'][0],$filter)) 
     $result[] = $data; 
} 
print_r($result); 

$result将只包含random2 & random3

Answer 2

results是一个数组，所以你得到了数组中的第一个由这样的：$json["results"][0]。

如果要遍历所有的值，它应该是这样的：

foreach($json["results"] as $data) { 
    echo json_encode($data['response']); 

} 

Answer 3

foreach($json["results"] as $data) { echo json_encode($data['response']);}