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我使用的是朋友类,我想从我的列表类中调用DeleteItem时使用rec的析构函数。但是,有一个指向我要删除的记录的指针,所以我不知道如何调用析构函数,以便它能够完成我想要的操作。 类:调用朋友类的析构函数
class rec
{
friend class list;
private:
char * id;
char firstname[15];
char lastname[15];
int ar[10];
rec* prev;
rec* next;
public:
void SetData (char * id_in, char * fn, char * ln, int * ans_in);
rec(char *i, char *fn, char *ln, int *a);
rec();
void operator= (const rec& r);
rec (const rec& r);
void Print();
~rec();
};
class list
{
private:
rec* first;
rec* last;
public:
int AddItem(rec r);
int DeleteItem (char* delid);
void PrintList(int order);
int ReadData(char *inanswer, char *inkey);
int WriteData(char *answer, char *key);
list();
void operator= (list l);
private:
int CheckDuplicate(rec r);
void DeleteData();
int Count(char *filename);
};
〜REC()
rec :: ~rec()
{
if (id != NULL)
{
delete [] id;
}
}
DeleteItem(Snipet)当我尝试
int list :: DeleteItem(char *delid)
{
int id_counter;
rec *current = first;
while (current || current == NULL)
{
if (current == NULL)
{
return 0;
}
else
{
id_counter = strcmp(current -> id, delid);
if (id_counter != 0)
{
current = current -> next;
}
else
{
if (current == first && current != last)
{
~rec(); //Here
first = current -> next;
delete current;
first -> prev = NULL;
return 1;
}
删除项目将编译好的,如果我手动放在delete[] current ->id;
,但做到这一点按原样编译
list.cpp:292: error: no match for ‘operator~’ in ‘~rec()’
/usr/lib/gcc/x86_64-redhat-linux/4.3.0/../../../../include/c++/4.3.0/bits/ios_base.h:105: note: candidates are: std::_Ios_Fmtflags std::operator~(std::_Ios_Fmtflags)
/usr/lib/gcc/x86_64-redhat-linux/4.3.0/../../../../include/c++/4.3.0/bits/ios_base.h:145: note: std::_Ios_Openmode std::operator~(std::_Ios_Openmode)
/usr/lib/gcc/x86_64-redhat-linux/4.3.0/../../../../include/c++/4.3.0/bits/ios_base.h:183: note: std::_Ios_Iostate std::operator~(std::_Ios_Iostate)
它是我的析构函数需要修复还是在DeleteItem中做的事情?
请正确格式化您的代码以便在此处可读。 –
你认为解决你的问题没有“朋友”,因为它是坏习惯 – 21koizyd
你几乎不应该明确调用析构函数。当然不适合这个班。你也应该避免原始指针和数组。改用std :: string,std :: vector和std :: shared_ptr/std :: unique_ptr。 –