2015-04-01 54 views
0

你好,我有问题在列表视图中显示图片。我有一个网址的数组,我必须下载图片,但为了测试目的,我尝试从我的本地硬盘驱动器填充每行相同的图片。我可以绑定数据,但到目前为止,我可以打印到图片collumn的唯一的事情就是对象的名称,但不是图片本身(DisplayData.Image)这是我的XAML和C#代码:无法在列表视图中显示图片

XAML

<Window x:Class="TestIT.MainWindow" 
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" 
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" 
    xmlns:local="clr-namespace:TestIT" 
    Title="MainWindow" Height="510.9" Width="723"> 
<Window.Resources> 
    <local:InterfaceBinding x:Key="adjust" /> 
</Window.Resources> 
<Grid> 
    <Grid HorizontalAlignment="Stretch" Height="100" VerticalAlignment="Stretch" Width="517" Margin="98,10,100,370" > 
     <Grid.ColumnDefinitions> 
      <ColumnDefinition Width="*"/> 
      <ColumnDefinition Width="*"/> 
      <ColumnDefinition Width="*"/> 
      <ColumnDefinition Width="*"/> 
      <ColumnDefinition Width="*"/> 
      <ColumnDefinition Width="*"/> 


     </Grid.ColumnDefinitions> 
     <Grid.RowDefinitions> 
      <RowDefinition Height="100" /> 
     </Grid.RowDefinitions> 

     <Label x:Name="labelNewsTop" Content="Top News" Grid.Row="0" HorizontalAlignment="Center" Margin="0,0,0,0" VerticalAlignment="Center" Grid.Column="0" MouseLeftButtonUp="labelNewsTop_MouseLeftButtonUp" /> 
     <Label x:Name="labelNewsBusiness" Content="Business" Grid.Row="0" HorizontalAlignment="Center" Margin="0,0,0,0" VerticalAlignment="Center" Grid.Column="1" /> 
     <Label x:Name="labelNewsTechnology" Content="Technology" Grid.Row="0" HorizontalAlignment="Center" Margin="0,0,0,0" VerticalAlignment="Center" Grid.Column="2" /> 
     <Label x:Name="labelNewsEntertainment" Content="Entertainment" Grid.Row="0" HorizontalAlignment="Center" Margin="0,0,0,0" VerticalAlignment="Center" Grid.Column="3" /> 
     <Label x:Name="labelNewsScience" Content="Sport" Grid.Row="0" HorizontalAlignment="Center" Margin="0,0,0,0" VerticalAlignment="Center" Grid.Column="4" /> 
     <Label x:Name="labelNewsHealth" Content="Health" Grid.Row="0" HorizontalAlignment="Center" Margin="0,0,0,0" VerticalAlignment="Center" Grid.Column="5" /> 
     <Image x:Name="iamgetest" Grid.ColumnSpan="2" HorizontalAlignment="Left" Height="100" Margin="24,68,0,-68" VerticalAlignment="Top" Width="100" Grid.Column="4"/> 

    </Grid> 
    <ListView x:Name="testView" HorizontalAlignment="Left" Height="304" Margin="0,105,0,0" VerticalAlignment="Top" Width="715"> 
     <ListView.View> 
      <GridView> 
       <GridViewColumn Header="Name" DisplayMemberBinding="{Binding Path=Name}"/> 
       <GridViewColumn Header="Value" DisplayMemberBinding="{Binding Path=Value}"/> 
       <GridViewColumn Header="Lele" > 
        <GridViewColumn.CellTemplate> 
         <DataTemplate> 
          <Image Height="50" Width="50" Stretch="Fill" Source="{Binding Path=Image}"></Image> 

         </DataTemplate> 
        </GridViewColumn.CellTemplate> 
       </GridViewColumn> 
      </GridView> 
     </ListView.View> 
    </ListView> 

</Grid> 
</Window> 

C#

 GNews gnews = new GNews(); 
     List<NewsModel> bla = gnews.getTopNews(); 


     for (int i = 0; i < bla.Count - 1; i++) 
     { 


      DisplayData data = new DisplayData(); 
      data.Name = bla[i].title; 
      data.Value = bla[i].url; 
      ImageSource mySource = new BitmapImage(new Uri("D:\\New folder\\New folder\\other\\Wall\\010.jpg")); 
      data.Image = new Image(); 
      data.Image.Source = mySource; 

      this.testView.Items.Add(data); 

     } 
    } 
} 

public class DisplayData 
{ 
    public string Name { get; set; } 
    public string Value { get; set; } 

    public Image Image { get; set; } 

}

回答

1

你应该结合开放的我们不是一个图像。然后

public class DisplayData 
{ 
    public string Name { get; set; } 
    public string Value { get; set; } 

    public Uri Image { get; set; } 
} 

你的循环会看起来像

for (int i = 0; i < bla.Count - 1; i++) 
    { 


     DisplayData data = new DisplayData(); 
     data.Name = bla[i].title; 
     data.Value = bla[i].url; 

     data.Image = new Uri("D:\\New folder\\New folder\\other\\Wall\\010.jpg"); 


     this.testView.Items.Add(data); 

    } 
+0

哦TY完美的作品...什么是这个在线托管,因为我需要一点时间来下载他们所有的照片组合的最佳方式。我应该把所有东西放在不同的线程上吗?并再次感谢answere这是真的很快:) – Proxy 2015-04-01 21:50:46

+0

如果你不需要明确地下载它们,你可以把你的URI作为一个http资源 – 2015-04-01 21:54:09

+0

我不明白你在说什么知道...你的意思是我应该使用http请求或?下载它们 – Proxy 2015-04-01 22:00:24