给我总是当我运行我的代码警告:mysql_fetch_assoc()预计参数1是资源,布尔在
0:
Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\fyp\admin_vieworders_details.php on line 12
Query Failed!You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
这里得到这个错误是我的数据库
表order_detail {Order_Detail_ID(PK) ,Order_Quantity,SUB_TOTAL}
表顺序{Order_ID上,order_date的,Order_Time,Delivery_Charge,Delivery_Name}
这里是我的代码
$orderid [email protected]$_GET["id"];
$detail = "SELECT
order.*,
order_detail.Order_Quantity,
order_detail.Sub_Total
FROM `order` AS a, `order_detail` AS b
WHERE order_detail.Order_ID = `order`.Order_ID AND order_detail.Order_Detail_ID=$orderid";
$result = mysql_query($detail);
$row = mysql_fetch_assoc($result);
if($result === FALSE)
{
die("Query Failed!".mysql_error().$result);
}
**警告:**'mysql_ *'功能被弃用PHP 5.5.0的,并会在将来被移除。相反,[MySQLi](http://www.php.net/manual/en/book.mysqli.php)或[PDO_MySQL](http://www.php.net/manual/en/ref.pdo-应该使用mysql.php)扩展名。 –
如果它包含值,你试过在这个查询之前echo'$ orderid'吗? –
@Jess Tan:说真的,请看看标有** Related **的右栏。我们知道每个人的问题都很特殊,但这只是一个常见的错误。 – hakre