编辑 - 因为我无法Strava这个标签这里是文档,如果你有兴趣 - http://strava.github.io/api/Get请求活动strava V3 API的Python
我通过认证得很好,并获得的access_token(和我运动员信息)在一个response.read。
我在下一步遇到问题: 我想返回有关特定活动的信息。
import urllib2
import urllib
access_token = str(tp[3]) #this comes from the response not shown
print access_token
ath_url = 'https://www.strava.com/api/v3/activities/108838256'
ath_val = values={'access_token':access_token}
ath_data = urllib.urlencode (ath_val)
ath_req = urllib2.Request(ath_url, ath_data)
ath_response = urllib2.urlopen(ath_req)
the_page = ath_response.read()
print the_page
误差
Traceback (most recent call last):
File "C:\Users\JordanR\Python2.6\documents\strava\auth.py", line 30, in <module>
ath_response = urllib2.urlopen(ath_req)
File "C:\Users\JordanR\Python2.6\lib\urllib2.py", line 124, in urlopen
return _opener.open(url, data, timeout)
File "C:\Users\JordanR\Python2.6\lib\urllib2.py", line 389, in open
response = meth(req, response)
File "C:\Users\JordanR\Python2.6\lib\urllib2.py", line 502, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Users\JordanR\Python2.6\lib\urllib2.py", line 427, in error
return self._call_chain(*args)
File "C:\Users\JordanR\Python2.6\lib\urllib2.py", line 361, in _call_chain
result = func(*args)
File "C:\Users\JordanR\Python2.6\lib\urllib2.py", line 510, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 404: Not Found
404是一个谜,因为我知道这个活动的存在呢?
'access_token'是否正确的标题信息? 该文档(http://strava.github.io/api/v3/activities/#get-details)使用授权:承载?我不确定liburl如何编码信息的承载部分?
对不起,如果我的一些术语有点偏离,我是新手。
回答了这个坏男孩。
import requests as r
access_token = tp[3]
ath_url = 'https://www.strava.com/api/v3/activities/108838256'
header = {'Authorization': 'Bearer 4b1d12006c51b685fd1a260490_example_jklfds'}
data = r.get(ath_url, headers=header).json()
它需要在“词典”中添加“承载”部分。
感谢您的帮助idClark
我也无法理解承载参数。你有没有尝试从命令行击中端点?如果我做'curl -XGET https://www.strava.com/api/v3/activities/111008284 -H“授权:持证人my_access_token_goes_here”| jq'。''我可以找回JSON就好了。稍后我会尝试使用Python。 – idclark