输出大型结构到HD

Question

我有一个大型结构阵列，我试图输出到硬盘驱动器。我似乎能够写入硬盘驱动器（虽然很难通过查看二进制数据来验证），但是当我尝试读取它时，总是会出现乱码。任何想法我做错了什么？

这里的结构配置：

class xyz 
{ 
public: 
    double x, y, z; 
}; 
class trianglePackage 
{ 
public: 

    int score; 
    int position; 

    xyz contactCoordinates; 
    xyz normalVector; 
    xyz locatorOffset; 

}; 
class quadanglesOutput 
{ 
public: 

    int locator1position, locator2position, locator3position, locator4position; 

    xyz centroid; 

    int surfaceAreaScore; 
    int centroidDifferance1Score; 
    int centroidDifferance2Score; 
    int minDistance1Score; 
    int minDistance2Score; 

    int totalLocatorScore; 
    int totalHullScore; 
    int totalScore; 

    double surfaceArea; 
    double centroidDifferance1; 
    double centroidDifferance2; 
    double minDistance1; 
    double minDistance2; 

    int hull; 

    trianglePackage locator1, locator2, locator3, locator4; 
}; 

和此处我使用的读/写功能：

void outputQuadangleOutput(quadanglesOutput* output, string description, param parameters) 
{ 

    string outputName = parameters.fileName + " " + description + ".bin"; 
    cout << "Output " << outputName.c_str() << "..."; 
    ofstream output2; 
    output2.open(outputName.c_str()); 
    output2.write(reinterpret_cast<char*>(output), streamsize(parameters.topXlist * sizeof(quadanglesOutput))); 
    output2.close(); 
    cout << "done" << endl; 

} 
void readIn(quadanglesOutput* pointer, param parameters, string description) 
{ 
    string fileName = parameters.fileName + " " + description + ".bin"; 
    cout << "openining " << fileName << "..."; 
    ifstream readFile; 
    readFile.open(fileName.c_str()); 
    readFile.read(reinterpret_cast<char*>(pointer), (parameters.topXlist * sizeof(quadanglesOutput))); 
    readFile.close(); 
    cout << "done" << endl; 
} 

通常结构的阵列在长度约100，但通常只有关于前25个回读正确，其他一切都是默认的未初始化数据。

我99％确定它的代码有问题，但是它有可能与四字节对齐有关吗？

谢谢。

Answer 1

这可能是字节对齐的问题，请使用pragma。 尝试包装类各地的

#PRAGMA PACK PUSH(1) 
.... 
#PRAGMA PACK POP 

或

#PRAGMA PACK(1) 
struct{ 
.. 
} 

尝试那些还有：为流
力二进制标志。

的ios_base ::二进制

readFile.open(fileName.c_str(), ios_base::binary); 

尝试刷新流。

stream.write(...) 
stream.flush() 

//我知道close（）应该刷新它。

UPDATE：
一切工作对我来说：

#include <iostream> 
#include <fstream> 
#include <string> 
#include <stdlib.h> 

using namespace std; 
#pragma pack(1) 
class xyz 
{ 
public: 
    double x, y, z; 
}; 

#pragma pack(1) 
class trianglePackage 
{ 
public: 

    int score; 
    int position; 

    xyz contactCoordinates; 
    xyz normalVector; 
    xyz locatorOffset; 

}; 

#pragma pack(1) 
class quadanglesOutput 
{ 
public: 

    int locator1position, locator2position, locator3position, locator4position; 

    xyz centroid; 

    int surfaceAreaScore; 
    int centroidDifferance1Score; 
    int centroidDifferance2Score; 
    int minDistance1Score; 
    int minDistance2Score; 

    int totalLocatorScore; 
    int totalHullScore; 
    int totalScore; 

    double surfaceArea; 
    double centroidDifferance1; 
    double centroidDifferance2; 
    double minDistance1; 
    double minDistance2; 

    int hull; 

    trianglePackage locator1, locator2, locator3, locator4; 
}; 

class param 
{ 
public: 
    string fileName; 
    int topXlist; 
}; 


void outputQuadangleOutput(quadanglesOutput* output, string description, param parameters) 
{ 

    string outputName = parameters.fileName + " " + description + ".bin"; 
    cout << "Output " << outputName.c_str() << "..."; 
    ofstream output2; 
    output2.open(outputName.c_str()); 
    output2.write(reinterpret_cast<char*>(output), streamsize(parameters.topXlist * sizeof(quadanglesOutput))); 
    output2.close(); 
    cout << "done" << endl; 

} 
void readIn(quadanglesOutput* pointer, param parameters, string description) 
{ 
    string fileName = parameters.fileName + " " + description + ".bin"; 
    cout << "openining " << fileName << "..."; 
    ifstream readFile; 
    readFile.open(fileName.c_str()); 
    readFile.read(reinterpret_cast<char*>(pointer), (parameters.topXlist * sizeof(quadanglesOutput))); 
    readFile.close(); 
    cout << "done" << endl; 
} 



int main(int argc, char *argv[]) 
{ 

    quadanglesOutput a = {0}; 
    cout<<"total score:"<<a.totalScore<<endl; 
    cout<<"locator position:"<<a.totalScore<<endl; 
    cout<<"locator position:"<<a.locator1.position<<endl; 
    cout<<"locator position:"<<a.locator2.normalVector.y <<endl; 
    cout<<"sizeof quadangsomething:"<<sizeof(quadanglesOutput)<<endl; 
    a.totalScore=1; 
    a.locator1.position=333445; 
    a.locator2.normalVector.y = 999.3224; 
    cout<<"total score:"<<a.totalScore<<endl; 
    cout<<"locator position:"<<a.locator1.position<<endl; 
    cout<<"locator position:"<<a.locator2.normalVector.y <<endl; 
    param p = {"C:/", 1}; 
    outputQuadangleOutput(&a, "file1", p); 

    quadanglesOutput *b = new quadanglesOutput(); 
    readIn(b, p, "file1"); 
    cout<<"new total score:"<<b->totalScore<<endl; 
    cout<<"new locator position:"<<b->locator1.position<<endl; 
    cout<<"new locator position:"<<b->locator2.normalVector.y <<endl; 

    delete b; 





    string asdf; 
    cin>>asdf; 

}; 

OUTPUT：
总比分：0
定位器位置：0
locator2.normalVector.y：0
的sizeof quadangsomething：436
总得分：1
定位器位置：333445
locator2.normalVector.y：999.322
输出C：/ file1.bin ...做
openining C：/ file1.bin ...做
新总得分：1
新定位器位置：333445
new locator2.normalVector.y：999。322

没有编译它仍然是正确的，但你可以看到在规模上的差异：

的sizeof quadangsomething：440

但打包发送结构上网络时，这是件好事。
因为这里的系统始终以相同的方式对其进行排列。