我被存在和不存在的关键字卡住。如果b条件不存在,则使用条件a进行Oracle SQL选择
我有一个表(Oracle门户表),其中有总结,以下结构:
ID LANGUAGE CAPTION
1 NL DUTCH CAPTION
1 F FRENCH CAPTION
2 NL DUTCH CAPTION
3 F FRENCH CAPTION
我需要一个选择总是选择每个ID两行,即使A F行或NL行不存在。然后,该行应在列的语言不存在的语言,但与现有行的标题(用语言F)
进行选择,以便查询的输出应该是:
ID LANGUAGE CAPTION
1 NL DUTCH CAPTION
1 F FRENCH CAPTION
2 NL DUTCH CAPTION
2 F DUTCH CAPTION
3 F FRENCH CAPTION
3 NL FRENCH CAPTION
这是可能?
非常好奇, ,已经是一个很大的感谢!
ps:我有这样的东西,但它完全不是我想要的。
SELECT id, language, display_name
FROM portal.wwsbr_all_folders p
WHERE caid = 55
AND DISPLAY_IN_PARENT_FOLDER = 1
AND ((upper(language) = 'NL' AND not exists (SELECT * FROM portal.wwsbr_all_folders p2 WHERE p.id = p2.id and language IN ('F')))
OR
(upper(language) = 'F' AND not exists (SELECT * FROM portal.wwsbr_all_folders p2 WHERE p.id = p2.id and language IN ('NL')))
)
AND parent_id = 4030963
ORDER BY sub_folder_sequence
编辑: 我得到正确的结果用下面的查询现在
(SELECT id, CASE language WHEN 'nl' THEN 'f' ELSE 'f' END lang, display_name
FROM portal.wwsbr_all_folders p
WHERE caid = 55
AND DISPLAY_IN_PARENT_FOLDER = 1
AND ((language = 'f' and exists(SELECT * FROM portal.wwsbr_all_folders p2 WHERE p2.id = p.id AND language = 'f'))
OR (language = 'nl' and not exists(SELECT * FROM portal.wwsbr_all_folders p2 WHERE p2.id = p.id AND language = 'f')))
AND parent_id = 4656102)
UNION ALL
(
SELECT id, CASE language WHEN 'f' THEN 'nl' ELSE 'nl' END lang, display_name
FROM portal.wwsbr_all_folders p
WHERE caid = 55
AND DISPLAY_IN_PARENT_FOLDER = 1
AND ((language = 'nl' and exists(SELECT * FROM portal.wwsbr_all_folders p2 WHERE p2.id = p.id AND language = 'nl'))
OR (language = 'f' and not exists(SELECT * FROM portal.wwsbr_all_folders p2 WHERE p2.id = p.id AND language = 'nl')))
AND parent_id = 4656102)
感谢您的回答,我刚刚发现了另一个解决方案,它也会返回正确的结果。我不知道哪一个更好(优化器和负载)...看看我在'问题'编辑 – Verthosa
@Verthosa我认为我的解决方案更快,你有更多的子查询。 –
tnx很多人! – Verthosa