我想我可能会在我的脑海里过于复杂。我有我想要使用,使在R的barplot文件看起来是这样的文件:从与read.table R的向量R
## metadata
# filepath
## filename
# Started on: Tue Jul 30 10:46:57 EDT 2013
#HISTOGRAM java.lang.Integer
READ: 1 2
-1 28 28
0 27 29
我想让我的数据的条形图。我认为它看起来有点像这样:
|
|
# | |
| | |
| | | |
|__|_____|____|___|____
-1(1) -1(2) 0(1) 0(2)
但是我在阅读数据时遇到了问题。这是我的代码:
# Parse the arguments
args <- commandArgs(trailing=T)
#Chart file
metricsFile <- args[1]
#pdf file path and name that I want to produce
outputFile <- args[2]
# Figure out where the firstLine and the chart are in the file and parse them out
startFinder <- scan(metricsFile, what="character", sep="\n", quiet=TRUE, blank.lines.skip=FALSE)
firstBlankLine=0
#finds empty strings
for (i in 1:length(startFinder))
{
if (startFinder[i] == "") {
if (firstBlankLine==0) {
firstBlankLine=i+1
} else {
secondBlankLine=i+1
break
}
}
}
#I accept some args and I read past some header information
firstLine <- read.table(metricsFile, header=T, nrows=1, sep="\t", skip=firstBlankLine)
#prints "firstLine: -1" "firstLine: 28" "firstLine: 28"
secondLine <- read.table(metricsFile, header=T, nrows=1, sep="\t", skip=secondBlankLine)
#prints "secondLine: -1" "secondLine: 27" "secondLine: 29"
# Then plot as a PDF
pdf(outputFile)
#I am just inputing firstLine here because I was trying to see how it works
#I get the error:'height' must be a vector or a matrix
barplot(firstLine,
main=paste("Read",(i-1)," Distribution ",
xlab="Counts",
ylab="F/R Orientation")
dev.off()
正如我在我的代码中评论我得到的错误,'高度'必须是一个向量或矩阵。我不知道R是否足够了解如何以矢量的形式读取它,而不是我目前正在做什么。我也不确定是否问题是我正在使用barplot。难道只是'阴谋'更好用吗?也许我错误地使用了read.table?
你可以让你的例子[reproducible](http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example)。否则,将无法进行调试。包括确切的输入文件或其中的一部分以及所使用的所有额外变量......您还可以包含'dput(firstLine)',这将对您有所帮助。 – Justin