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enter image description here请参阅附件图片。用NULL替换空白单元格?
我查询看的“漏洞”我们然而,当不存在漏洞,我的查询,没有返回细胞,甚至没有NULLS多少百分比(请详见附图)
有什么办法我可以得到这个只显示NULL或“100%”而不是空白单元格?
这里是我的查询
select *
from
(select '100' - convert(decimal(5,2),(100 * convert(float,CountBreach)/nullif(convert(float,CountNot),0))) AS '2 week target'
from
(select CancerBreach, COUNT(*) [CountBreach] from
(
SELECT
d.HospitalNumber ,
CASE WHEN SUM(DATEDIFF(DD,ReceiptOfReferralDate, FirstAppointmentDate)- FirstAppointmentWaitingTimeAdjusted) > 14
THEN 'Breach' ELSE 'Not Breach'
END AS CancerBreach
FROM [WH].[SCR].[Referral] R
LEFT OUTER JOIN WHREPORTING.LK.SpecialtyDivision S
ON CONVERT(Varchar(10),(R.SpecialtyCode)) = S.SpecialtyCode
LEFT JOIN WH.SCR.Demographic as d
on d.UniqueRecordId = R.DemographicUniqueRecordId
WHERE
R.FirstAppointmentOrganisationCode IN ('RM202', 'RM201')
AND PriorityTypeCode = '03'
AND FirstAppointmentDate BETWEEN '01 oct 2016' AND '14 oct 2016'
AND R.CancerTypeCode <> '16'
AND R.FirstAppointmentDate is not NULL
AND NewTumourSite IS NULL
and s.SpecialtyCode = '103'
GROUP BY
d.HospitalNumber)f
where CancerBreach = 'breach'
group by CancerBreach) e,
(select COUNT(*) [CountNot] from
(
SELECT
d.HospitalNumber ,
CASE WHEN SUM(DATEDIFF(DD,ReceiptOfReferralDate, FirstAppointmentDate)- FirstAppointmentWaitingTimeAdjusted) > 14
THEN 'Breach' ELSE 'Not Breach'
END AS CancerBreach
FROM [WH].[SCR].[Referral] R
LEFT OUTER JOIN WHREPORTING.LK.SpecialtyDivision S
ON CONVERT(Varchar(10),(R.SpecialtyCode)) = S.SpecialtyCode
LEFT JOIN WH.SCR.Demographic as d
on d.UniqueRecordId = R.DemographicUniqueRecordId
WHERE R.FirstAppointmentOrganisationCode IN ('RM202', 'RM201')
AND PriorityTypeCode = '03'
AND FirstAppointmentDate BETWEEN '01 oct 2016' AND '14 oct 2016'
AND R.CancerTypeCode <> '16'
AND R.FirstAppointmentDate is not NULL
AND NewTumourSite IS NULL
and s.SpecialtyCode = '103'
GROUP BY
d.HospitalNumber)f
where CancerBreach = 'Not breach'
group by CancerBreach) d)e