1
我可能是盲目的,但我无法解释为什么查询甲骨文:报价表名
SELECT "VALUE" AS value
FROM "TEST_INT"
WHERE "ID" = 20;
作品,但
SELECT "VALUE" AS value
FROM "TEST_INT" AS "TTT"
WHERE "ID" = 20;
没有。
我的SQL开发人员回复
ORA-00933: SQL command not properly ended
00933. 00000 - "SQL command not properly ended"
*Cause:
*Action:
Error at Line: 2 Column: 19
难道我引用表错误的名字吗?
啊,非常感谢! – gefei
+1是的,就是这样! – Parado