“new_dollars =美元+美分/ 100”无变化

Question

在输出中，new_dollars总是显示美元的数量，所以我不知道如何解决问题。请帮我弄清楚是什么问题。

int main(void) 
{ 
    int dollars, cents, count, new_dollars; 

    for (count = 1; count <= 10; ++count){ 
     printf ("Enter dollars: "); 
     scanf ("%i", &dollars); 

     printf ("Enter cents: "); 
     scanf ("%i", &cents); 

     if (cents >= 100){ 
      cents = cents % 100; 
      new_dollars = dollars + cents/100; 
      printf ("%i\n", new_dollars); 
      printf ("$%i.%2i\n\n", new_dollars, cents); 
     } 
     else {   
      printf ("$%i.%2i\n\n", dollars, cents); 
     } 
    } 

    return 0; 
} 

Answer 1

评论者对整数除法是正确的。试试这个，它有秩序两行做交换的计算，所以cents仍会有一个有用的值，当你需要它：

int main(void) 
{ 
    int dollars, cents, count, new_dollars; 

    for (count = 1; count <= 10; ++count){ 
     printf ("Enter dollars: "); 
     scanf ("%i", &dollars); 

     printf ("Enter cents: "); 
     scanf ("%i", &cents); 

     if (cents >= 100){ 
      new_dollars = dollars + cents/100; 
      cents = cents % 100; 
      printf ("%i\n", new_dollars); 
      printf ("$%i.%2i\n\n", new_dollars, cents); 
     } 
     else {   
      printf ("$%i.%2i\n\n", dollars, cents); 
     } 
    } 

    return 0; 
} 

Answer 2

1. 转换“INT new_dollars”到“浮new_dollars”;

2. new_dollars =（浮动）美元+（浮动）美分/ 100;

3. printf（“$％。2f \ n”，new_dollars）;