2012-09-20 100 views
4

我觉得自己像一个屁股踢腿比赛中的单腿男人......我需要添加一个属性到我的LINQ数据集中,该数据集根据子集合的属性提供摘要并然后压扁我的数据。 (我正在创建一个.rdlc数据集)。我终于想出了如何将我的数据变平,但我无法弄清楚如何根据哪一组审阅者提供他们的评估来推导出价值。总结基于子集合的属性

我有一些评估,我需要根据审稿小组总结一个结果审稿属于:

  1. 如果任何一个评审组的评估是“大问题”,返回“大问题”。
  2. 如果所有评估都说“无问题”,则返回“无问题”。
  3. 如果没有评估是“大问题”,并且至少有一个是空白,则返回null。

    下面是一个样本集我创建的希望证明什么,我说的是:

    public List<SummaryReport> CreateReport() 
    { 
        return Get() 
         .SelectMany(rev => rev.Assessments, (rev, ass) => new { rev, ass }) 
         .Select(x => new SummaryReport 
         { 
          ReviewID = x.rev.ReviewID, 
          ReviewerID = x.ass.Reviewer.ReviewerID, 
          Assessment = x.ass.Assessment, 
          ReviewGroupID = x.ass.Reviewer.ReviewGroup.ReviewGroupID, 
          GroupAssessment = "Need to derive this value!!??!?" 
          }) 
         .ToList(); 
    } 
    
    public List<Review> Get() 
    { 
        ReviewGroup GrpOne = new ReviewGroup(){ ReviewGroupID=1}; 
        ReviewGroup GrpTwo = new ReviewGroup(){ ReviewGroupID=2}; 
        ReviewGroup GrpThree = new ReviewGroup(){ ReviewGroupID=3}; 
    
        ReviewerInfo userOne = new ReviewerInfo() { ReviewerID=1, ReviewGroup = GrpOne}; 
        ReviewerInfo userTwo = new ReviewerInfo() { ReviewerID=2, ReviewGroup = GrpTwo}; 
        ReviewerInfo userThree = new ReviewerInfo() { ReviewerID=3, ReviewGroup = GrpTwo}; 
        ReviewerInfo userFour = new ReviewerInfo() { ReviewerID=4, ReviewGroup = GrpThree}; 
    
        Assessment asOne = new Assessment() { AssessmentID=1, Reviewer=userOne, Assessment="Big Problem"}; 
        Assessment asTwo = new Assessment() { AssessmentID=2, Reviewer=userTwo, Assessment="No Problem"}; 
        Assessment asThree = new Assessment() { AssessmentID=3, Reviewer=userThree, Assessment="No Problem"}; 
        Assessment asFour = new Assessment() { AssessmentID=4, Reviewer=userFour, Assessment=""}; 
    
        Assessment asFive = new Assessment() { AssessmentID=5, Reviewer=userOne, Assessment="No Problem"}; 
        Assessment asSix = new Assessment() { AssessmentID=6, Reviewer=userTwo, Assessment="No Problem"}; 
        Assessment asSeven = new Assessment() { AssessmentID=7, Reviewer=userThree, Assessment="No Problem"}; 
        Assessment asEight = new Assessment() { AssessmentID=8, Reviewer=userFour, Assessment="No Problem"}; 
    
        Assessment asNine = new Assessment() { AssessmentID=9, Reviewer=userOne, Assessment="No Problem"}; 
        Assessment asTen = new Assessment() { AssessmentID=10, Reviewer=userTwo, Assessment=""}; 
        Assessment asEleven = new Assessment() { AssessmentID=11, Reviewer=userThree, Assessment="No Problem"}; 
        Assessment asTwelve = new Assessment() { AssessmentID=12, Reviewer=userFour, Assessment="No Problem"}; 
    
        List<Assessment> firstList = new List<Assessment>() { asOne, asTwo, asThree, asFour }; 
        List<Assessment> secondList = new List<Assessment>() {asFive, asSix, asSeven, asEight}; 
        List<Assessment> thirdList = new List<Assessment>() { asNine, asTen, asEleven, asTwelve }; 
    
        Review revOne = new Review() { ReviewID=1, Assessments=firstList }; 
        Review revTwo = new Review() { ReviewID=2, Assessments = secondList }; 
        Review revThree = new Review() { ReviewID = 3, Assessments = thirdList }; 
    
        List<Review> reviews = new List<Review>() { revOne, revTwo, revThree }; 
    
        return reviews; 
    } 
    
    public class SummaryReport 
    { 
        public int ReviewID { get; set; } 
        public int ReviewerID { get; set; } 
        public string Assessment { get; set; } 
        public int ReviewGroupID { get; set; } 
        public string GroupAssessment { get; set; } 
    } 
    
    public class Review 
    { 
        public int ReviewID { get; set; } 
        public virtual List<Assessment> Assessments { get; set; } 
        public Review() { } 
    } 
    
    public class Assessment 
    { 
        public int AssessmentID { get; set; } 
        public ReviewerInfo Reviewer { get; set; } 
        public string Assessment { get; set; } 
    } 
    
    public class ReviewerInfo 
    { 
        public int ReviewerID { get; set; } 
        public ReviewGroup ReviewGroup { get; set; } 
    } 
    
    public class ReviewGroup 
    { 
        public int ReviewGroupID { get; set; } 
    } 
    
+0

样本数据的预期输出是什么? – Aducci

+2

我编辑了你的标题。请参阅:“[应该在其标题中包含”标签“](http://meta.stackexchange.com/questions/19190/)”,其中的共识是“不,他们不应该”。 –

+0

@Aducci - 我实际上正在尝试创建一个预期的输出结果,但在结束之前我看到了一个答案,因此我停下了脚步。谢谢! – Eclipse

回答

1

您可以定义一个方法,并且投影时调用它。

注:更改Assessment.Assessment属性Assessment.AssessmentDescription所以属性名称不会是一样的封闭类型

public List<SummaryReport> CreateReport() 
{ 
return Get() 
    .SelectMany(rev => rev.Assessments, (rev, ass) => new { rev, ass }) 
    .Select(x => new SummaryReport 
    { 
     ReviewID = x.rev.ReviewID, 
     ReviewerID = x.ass.Reviewer.ReviewerID, 
     Assessment = x.ass.Assessment, 
     ReviewGroupID = x.ass.Reviewer.ReviewGroup.ReviewGroupID, 
     GroupAssessment = DeriveGroupAssessment(x.rev.Assessments) 
     }) 
    .ToList(); 
} 


private static string DeriveGroupAssessment(IEnumerable<Assessment> assessments) 
{ 
    string assessment = null; 

    if (assessments.Any(a => a.AssessmentDescription == "Big Problem")) 
    { 
    assessment = "Big Problem"; 
    } 
    else if (assessments.All(a => a.AssessmentDescription == "No Problem")) 
    { 
    assessment = "No Problem"; 
    } 

    // If you want the value to be null if neither of the above conditions are met, this logic is not needed 
    ////if (!assessments.Any(a => a.AssessmentDescription == "Big Problem") 
    //// && assessments.Any(a => a.AssessmentDescription == string.Empty)) 
    ////{ 
    //// assessment = null; 
    ////} 

    return assessment; 
} 
+0

谢谢!我甚至没有想过要调用一种方法。我认为它必须是一个相对容易的解决方案。 – Eclipse

1

尝试,

public static List<SummaryReport> CreateReport() 
    { 
     return Get() 
      .SelectMany(rev => rev.Assessments, (rev, ass) => new { rev, ass }) 
      .Select(x => new SummaryReport 
      { 
       ReviewID = x.rev.ReviewID, 
       ReviewerID = x.ass.Reviewer.ReviewerID, 
       Assessment = x.ass.AssessmentStr, 
       ReviewGroupID = x.ass.Reviewer.ReviewGroup.ReviewGroupID, 
       GroupAssessment = x.rev.Assessments.Any(a => a.AssessmentStr == "Big Problem") ? "Big Problem" : 
       x.rev.Assessments.All(a => a.AssessmentStr == "No Problem")? "No Problem" : null 
      }) 
      .ToList(); 
    } 

的名称变更将属性评估为AssessmentStr,因为C#不允许属性名称与类名称相同。

+0

感谢您的回复。我敢肯定这个也会有效。我刚刚与杜加斯的回答一起去了,因为我在这之前见过他。 – Eclipse