我想我最好弄清楚如何去这个错误我感到reciving:VB.net跨线程操作无效
跨线程操作无效:控制“ListView1的”从访问线程不是它创建的线程。
我有一个背景工作即是从Excel工作表中提取单元格,并将它们放入列表视图。
在形式负载我这样做:
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Call createListView()
End Sub
Private Sub createListView()
ListView1.View = View.Details
ListView1.GridLines = True
ListView1.FullRowSelect = True
ListView1.HideSelection = False
ListView1.MultiSelect = False
ListView1.Columns.Add("Column Name", 150)
ListView1.Columns.Add("Column Number", 150)
End Sub
然后我所呼叫的用户之后BackgroundWorker的选择了一个文件:
If openFileDialog1.ShowDialog() = DialogResult.OK Then
stFilePathAndName = openFileDialog1.FileName
ProgressBar1.Style = ProgressBarStyle.Marquee
BGWxml2excel = New System.ComponentModel.BackgroundWorker
BGWxml2excel.WorkerReportsProgress = True
BGWxml2excel.WorkerSupportsCancellation = True
BGWxml2excel.RunWorkerAsync()
End If
然后我与得到的Excel列计数和值,使得处理我可以用它填充ListView:
Private Sub BGWxml2excel_DoWork(ByVal sender As Object, ByVal e As System.ComponentModel.DoWorkEventArgs) Handles BGWxml2excel.DoWork
Call xml2Excel(stFilePathAndName)
End Sub
Private Sub xml2Excel(ByRef theDirOfFile As String)
Dim xlsApp As Excel.Application
Dim xlsWB As Excel.Workbook
Dim xlsSheet As Excel.Worksheet
Dim columnCount As Integer = 0
xlsApp = New Excel.Application
xlsApp.Visible = False
xlsApp.DisplayAlerts = False
xlsWB = xlsApp.Workbooks.OpenXML(Filename:=theDirOfFile, LoadOption:=XlXmlLoadOption.xlXmlLoadImportToList)
xlsSheet = xlsWB.Worksheets(1)
xlsSheet.Select()
columnCount = xlsSheet.UsedRange.Columns.Count
Dim lvi As New ListViewItem
Dim x As Integer = 1
Do Until x = columnCount + 1
lvi.Text = xlsSheet.Cells(1, x).value
lvi.SubItems.Add(x)
ListView1.Items.Add(lvi)
x = x + 1
Loop
'xlsSheet.SaveAs("c:\_tempExcelFile.xlsx", FileFormat:=51, CreateBackup:=False)
xlsWB.Close()
xlsApp.Quit()
End Sub
的错误是在这条线:
ListView1.Items.Add(lvi)
我该怎么办才能纠正这个奇怪的proglem?
谢谢!
大卫
谢谢,RoadWarrior! :O) – StealthRT 2011-02-25 15:30:48