随机图像发生器，不重复xcode

Question

我将如何创建一个随机图像发生器，不重复的图像，直到它已经通过他们所有的一次？

例如：

- （IBAction为）randomimagebutton {

int randomimages = rand() % 5; 

switch (randomimages) { 

    case 0: 
     imageview.image = [UIImage imageNamed:@"IMAGE_001.png"]; 
     break; 
    case 1: 
     imageview.image = [UIImage imageNamed:@"IMAGE_002.png"]; 
     break; 
    case 2: 
     imageview.image = [UIImage imageNamed:@"IMAGE_003.png"]; 
     break; 
    case 3: 
     imageview.image = [UIImage imageNamed:@"IMAGE_004.png"]; 
     break; 
    case 4: 
     imageview.image = [UIImage imageNamed:@"IMAGE_005.png"]; 
     break; 

default: 

     break; 

} 

如果图像中出现的顺序为：1,4,2,5,4,3我怎么能确保在直到显示所有5张图像后，“4”才会再次出现？

感谢您的帮助！

Answer 1

将图像名称存储在NSMutableArray中，然后对数组进行混洗。如 this SO answer

然后遍历数组。

Answer 2

创建的NSMutableArray和每当选择一个随机数上它把0，1，2，3，4然后将其取下像这样：

[myNSMutableArray removeObjectAtIndex:myRandNumber]; 


To fill the gap, all elements beyond index are moved by subtracting 1 from their index. 

然后，只需通过执行选择新的随机：

int randomimages = rand() % 4; //4 would of course be a int var that you substract everytime a new random is generated. 

等等。