按列+ COUNT（*）分组，如何获得每个组合的平均计数？

Question

我有以下（简化）查询：

SELECT  ResolvedBy, COUNT(*) AS Count, fiCategory, fiSubCategory, fiSymptom 
FROM   tContact 
WHERE  (ResolvedBy IS NOT NULL) 
GROUP BY ResolvedBy, fiCategory, fiSubCategory, fiSymptom 
ORDER BY Count DESC 

现在我需要为每fiCategory, fiSubCategory, fiSymptom组合柱的平均计数。怎么做？

例如：

ResolvedBy Count fiCategory fiSubCategory fiSymptom Average 
    1   50   1    2    3   40 
    2   30   1    2    3   40 
    3   40   1    2    3   40 
    1   20   2    3    4   30 
    2   40   2    3    4   30 

在该示例中是fiCategory，fiSubCategory和fiSymptom的两种组合：1,2,32,3,4和。因此存在被计算的两个平均值：

1. 50 + 30 + 40/3 = 40
2. 20 + 40/2 = 30。

所以想要总结的每计数组合并划分出现的次数。

编辑：该示例是提取所需的查询结果。计数是每个ResolvedBy这个组合的所有出现的总和。

预先感谢您。

Answer 1

Select ResolvedBy, [Count], fiCategory, fiSubCategory, fiSymptom 
    , Avg(Z.Count) Over(Partition By fiCategory, fiSubCategory, fiSymptom) As AvgByGrp 
From (
     Select ResolvedBy, Count(*) As [Count], fiCategory, fiSubCategory, fiSymptom 
     From tContact 
     Group By ResolvedBy, fiCategory, fiSubCategory, fiSymptom 
     ) As Z 

Order By Z.Count Desc 

Answer 2

试试这个：

SELECT main.ResolvedBy, COUNT(*) AS Count, 
    main.fiCategory, main.fiSubCategory, main.fiSymptom, average 
FROM tContact main 
JOIN (SELECT COUNT(*)/count(distinct ResolvedBy) as average, 
     fiCategory, fiSubCategory, fiSymptom group by 2,3,4) x 
     on x.fiCategory = main.fiCategory 
     and x.fiSubCategory = main.fiSubCategory 
     and x.fiSymptom = main.fiSymptom 
WHERE main.ResolvedBy IS NOT NULL 
GROUP BY 1, 3, 4, 5 
ORDER BY 2 DESC