当我在输入中插入字符串时,我遇到更新问题。我的列“位置”我想更新的是一个数据类型:varchar()在我的数据库中。我可以插入一个数字,如“3”,它将在数据库中更新。但是,当我插入像“SS14”字符串它不会更新数据库,我会得到一个错误。我做错了什么?不能更新值作为字符串
<?php
try {
// verify request
if($_SERVER['HTTP_X_REQUESTED_WITH'] != 'XMLHttpRequest') throw new Exception ('No Xrequest');
require_once('db.php');
$q= 'UPDATE prestashop.ps_product SET location = %s WHERE id_product = %d';
$sql = sprintf($q, $_REQUEST['value'], $_REQUEST['id']);
$rs=$ib->exec($sql);
if (PEAR::isError($rs)) throw new Exception ("DB Request: ". $rs->getMessage());
die("1"); // exit and return 1 on success
} catch (Exception $e) {
print $e->getMessage();
} '
<td class="test" id="'.$r["product_id"].'"><font size=+2>
<b>'.$r["product_s_desc"].'</b></font></td>
<script>
var x;
var h = 0; // blur fires multiple times, use h to count and fire once
var url = 'up.php';
$(".test").on('click', function(d) {
d.stopPropagation();
var x = $(d.target);
x.html('<input id="edit" style="width: 40px;" value="'+x.text()+'">');
var this_id = x.context.id;
$("#edit").on('blur', function(d) {
if (h < 1) {
h = h+1;
d.stopPropagation();
$(d.target.parentElement).text(d.target.value);
$.get(url, {id: this_id, value: d.target.value})
.done(function(d){ if(d == undefined || d != 1) { alert('Something went wrong, check your data and results. '+d);}})
.fail(function(d){ alert('error');});
$(".edit").off('blur');
}
return false;
});
h = 0;
});
</script>
该代码不是在“代码块”中的正确顺序,但我只是显示我使用的代码 – Somepub