如何将数组中的值传递给构造函数？ C++

Question

我创建了一个程序，用于从文件中读取数据并从中创建对象。然而，它们的值可能会有所不同，因此我创建了一个可以扩展到一定数量的数组。当我尝试通过构造函数传递时遇到了一些麻烦。此外，我不应该使用从我理解会使这容易很多的载体。

    //bunch of code to read in data from the file similar to this below 
     getline (readfile, typea); 

        //code determining what each data type is.   

readMedia >>NSA_Value; 
for (int i=0; i<=NSA_Value; i++){ 
getline(readMedia, supporting_actorsa[i]); //this is the array I'm using that can grow a bit to accommodate. 

Vhs initial = Vhs(typea, a, b, c, supporting_actorsa[10]); //the constructor ive removed most of the other things to make it more readable. 

这是它调用上创建对象

#include "Vhs.cpp" 


Vhs::Vhs (string type, string a1, string b1, string c1, supporting_actorsa1[10]) 
{ 
} 
Vhs::Vhs(void) 
{ 
} 


Vhs::~Vhs(void) 
{ 
} 

cpp文件，这这这是.h文件中

#pragma once 
class Vhs 
{ 

public: 

    Vhs(void); 
    Vhs (string type, string A2, string B2, string C3, string supporting_actorsA3[10]); 
~Vhs(void); 


}; 

所有的变量存在，我只是删除所有声明让事情看起来更干净。 感谢您的帮助

Answer 1

你可以通过一个C-阵列像这样：

#include <iostream> 
#include <string> 
using namespace std; 
class Vhs { 
public: 
    Vhs (string type, string A2, string B2, string C3, 
     string *supporting_actorsA3, int n); 
}; 
Vhs::Vhs (string type, string a1, string b1, string c1, 
      string *supporting_actorsa1, int n) { 
    for (int i = 0; i < n; i++) { 
    cout << supporting_actorsa1[i] << endl; 
    } 
} 

int main() 
{ 
    string supporting_actorsa[1024]; 
    int num_actors; 
    num_actors = 2; 
    supporting_actorsa[0] = "1"; 
    supporting_actorsa[1] = "2"; 
    Vhs initial = Vhs("typea", "a", "b", "c", supporting_actorsa, 
     num_actors); 
    return 0; 
}