2015-06-24 52 views
0

我将一个祖先表加入到一个查询中,该查询给出了预期的结果,但是在少数情况下,它会根据“客户端”返回多个行。我只需要返回列中'MAX'条目的行。SQL - n层联接语句

SELECT  C.FULL_NAME_ALTERNATE || ' (' || C.CLIENT_NUMBER || ')' AS CLIENT, 
      SA.ORGANIZATION_ID         AS SA_ORG, 
      SA.PROGRAM_NAME          AS PROGRAM, 
      CPA.PROCEDURES          AS PROCEDURE, 
      SUM(SA.ACTIVITY_UNIT)        AS USED_UNITS, 
      AP.DEFAULT_PROCEDURE_FEE       AS FEE, 
      (SUM(SA.ACTIVITY_UNIT) * AP.DEFAULT_PROCEDURE_FEE) AS USED_DOLLARS, 
      AP.ORGANIZATION_ID         AS AP_ORG 

FROM  RPT_CLIENT   C 
INNER JOIN RPT_CLIENT_PAYER_AUTH CPA ON C.CLIENT_ID = CPA.CLIENT_ID 
INNER JOIN RPT_SCHEDULED_ACTIVITIES SA ON SA.ACTIVITY_DETAIL_ID = CPA.ACTIVITY_DETAIL_ID 
INNER JOIN RPT_ORGANIZATION_RELATIVE R ON R.DESCENDANT_ORG_ID = CPA.ORGANIZATION_ID 
INNER JOIN RPT_ADMIN_PROCEDURE  AP ON CPA.PROCEDURES = AP.PROCEDURE_CODE               
            AND (AP.END_DATE > CURRENT_DATE OR AP.END_DATE IS NULL) 
            AND AP.ORGANIZATION_ID = R.ANCESTOR_ORG_ID 

GROUP BY C.FULL_NAME_ALTERNATE || ' (' || C.CLIENT_NUMBER || ')', 
      SA.ORGANIZATION_ID, 
      SA.PROGRAM_NAME, 
      CPA.PROCEDURES, 
      AP.DEFAULT_PROCEDURE_FEE, 
      AP.ORGANIZATION_ID 

这将返回类似以下内容:

CL ID PROG PROC UNIT DOLLARS  FEE SA_ID 
Bob 1029 ACH W7075 4069 37272.04 9.16 1029 
Bob 1142 RCH W6099 344  5149.68  14.97 1142 
Bob 1142 RCH W6099 344  5772.32  16.78 1137 
Jen 1029 ACH W7074 3898 17541  4.5  1029 
Jen 1024 BEH W7095 55  1068.1  19.42 1024 
Jen 1142 RES W6099 343  5134.71  14.97 1142 
Jen 1142 RES W6099 343  5755.54  16.78 1137 
Dave 1186 RES W6098 350  64004.5  182.87 1137 
Dave 1186 RES W6098 350  64004.5  182.87 1186 
Dave 1186 RES W6099 350  5873  16.78 1137 
Dave 1186 RES W6099 350  5873  16.78 1186 

我需要返回每个客户端,身份证,计划和程序只有1行。当有多个时,需要使用带有max(sa_id)的行。
* sa_id和id并不总是匹配,但是当它们这样做时,它们将被选中。


+0

是'sa_id'唯一列,或者是在同一个客户端有多个具有相同'sa_id'的记录?您提供的示例输出的示例数据会很有帮助。 :) –

+0

示例结果中的列名与您提供的查询中的选定列不匹配。 –

回答

0

的关键是添加过滤掉SA记录如下是不是你的加入条款的最大SA发表正式声明:

SELECT  C.FULL_NAME_ALTERNATE || ' (' || C.CLIENT_NUMBER || ')' AS CLIENT, 
      SA.ORGANIZATION_ID         AS SA_ORG, 
      SA.PROGRAM_NAME          AS PROGRAM, 
      CPA.PROCEDURES          AS PROCEDURE, 
      SUM(SA.ACTIVITY_UNIT)        AS USED_UNITS, 
      AP.DEFAULT_PROCEDURE_FEE       AS FEE, 
      (SUM(SA.ACTIVITY_UNIT) * AP.DEFAULT_PROCEDURE_FEE) AS USED_DOLLARS, 
      AP.ORGANIZATION_ID         AS AP_ORG 

FROM  RPT_CLIENT   C 
INNER JOIN RPT_CLIENT_PAYER_AUTH CPA ON C.CLIENT_ID = CPA.CLIENT_ID 
INNER JOIN RPT_SCHEDULED_ACTIVITIES SA ON SA.ACTIVITY_DETAIL_ID = CPA.ACTIVITY_DETAIL_ID 
INNER JOIN RPT_ORGANIZATION_RELATIVE R ON R.DESCENDANT_ORG_ID = CPA.ORGANIZATION_ID 
INNER JOIN RPT_ADMIN_PROCEDURE  AP ON CPA.PROCEDURES = AP.PROCEDURE_CODE               
            AND (AP.END_DATE > CURRENT_DATE OR AP.END_DATE IS NULL) 
            AND AP.ORGANIZATION_ID = R.ANCESTOR_ORG_ID 
and sa_id = (select max(sa_id) from RPT_SCHEDULED_ACTIVITIES x where x.ACTIVITY_DETAIL_ID = CPA.ACTIVITY_DETAIL_ID) 

GROUP BY C.FULL_NAME_ALTERNATE || ' (' || C.CLIENT_NUMBER || ')', 
      SA.ORGANIZATION_ID, 
      SA.PROGRAM_NAME, 
      CPA.PROCEDURES, 
      AP.DEFAULT_PROCEDURE_FEE, 
      AP.ORGANIZATION_ID