5

如何将多个字符串添加到字符串中? 最简单的方法是什么? 如果我不想每次我添加了一些字符串时创建新的代码行,我想要做这样的事情:将多个字符串添加到字符串中

NSString *recipeTitle = [@"<h5>Recipe name: " stringByAppendingFormat:recipe.name, @"</h5>"]; 
    NSLog(@"%@", recipeTitle); 

    // This shows: <h5>Recipe name: myrecipe 
    // Where's the </h5> closing that header ? It will only show up with the next line of code 

    recipeTitle = [recipeTitle stringByAppendingFormat:@"</h5>"]; 

    //my problem is that will result in more than 1k lines of programming 

我一定要一定添加一个新行追加每次都附上? 有没有更快捷/更有成效的方式来做到这一点?

我想用我的tableview在其中编写电子邮件正文,这将导致一组巨大的编程线。有没有人可以给我任何提示或任何比编写huuuge字符串更好的东西,所以我可以用包含我的tableview数据的表填充我的电子邮件正文?

任何帮助,使这个更高效的赞赏。谢谢 ! 卡洛斯法里尼。

//它的工作一点我弄了:

-(IBAction)sendmail{ 
MFMailComposeViewController *composer = [[MFMailComposeViewController alloc] init]; 
[composer setMailComposeDelegate:self]; 
NSString *recipeTitle = @"<h5>Recipe name: "; 
recipeTitle = [recipeTitle stringByAppendingFormat:recipe.name]; 
recipeTitle = [recipeTitle stringByAppendingFormat:@"</h5>"]; 

NSString *ingredientAmount = @""; 
NSString *ingredientAisle = @""; 
NSString *ingredientTitle = @""; 

NSString *tableFirstLine = @"<table width='90%' border='1'><tr><td>Ingredient</td><td>Amount</td><td>Aisle</td></tr>"; 
NSString *increments = @""; 
int i=0; 

for (i=0; i < [ingredients count]; i++) { 
    Ingredient *ingredient = [ingredients objectAtIndex:i]; 
    ingredientTitle = ingredient.name; 
    ingredientAmount = ingredient.amount; 
    ingredientAisle = ingredient.aisle; 

    increments = [increments stringByAppendingFormat:recipeTitle]; 
    increments = [tableFirstLine stringByAppendingFormat:@"<tr><td>"]; 
    increments = [increments stringByAppendingFormat:ingredientTitle]; 
    increments = [increments stringByAppendingFormat:@"</td><td>"]; 
    increments = [increments stringByAppendingFormat:ingredientAmount]; 
    increments = [increments stringByAppendingFormat:@"</td><td>"]; 
    increments = [increments stringByAppendingFormat:ingredientAisle]; 
    increments = [increments stringByAppendingFormat:@"</td></tr>"]; 
    if (i == ([ingredients count]-1)) { 
     //IF THIS IS THE LAST INGREDIENT, CLOSE THE TABLE 
     increments = [increments stringByAppendingFormat:@"</table>"]; 
    } 
} 

NSLog(@"CODE:: %@", increments); 

if ([MFMailComposeViewController canSendMail]) { 
    [composer setToRecipients:[NSArray arrayWithObjects:@"[email protected]", nil]]; 
    [composer setSubject:@"subject here"]; 
    [composer setMessageBody:increments isHTML:YES]; 
    [composer setModalTransitionStyle:UIModalTransitionStyleFlipHorizontal]; 
    [self presentModalViewController:composer animated:YES]; 
    [composer release]; 
}else { 
    [composer release]; 
} 

}

但话又说回来,它显示在表中只有一行。我在这里做错了什么?

回答

5

怎么是这样的:

NSString *recipeTitle = [NSString stringWithFormat:@"<h5>Recipe name: %@ </h5>", recipe.name]; 
+0

我可以把多个%@,然后去喜欢......,recipe.name,recipe.preptime,recipe.included?我会在同一行代码中附加三个字符串。这不会是坏... – Farini

+1

是的,你可以。您也可以查看文档以获取更多生成字符串的方法。 – Odrakir

+0

这很完美。谢谢你的启发 – Farini