2012-11-16 87 views
1

我有这个疑问这有助于我获得点当前用户,现在,我对设置条件的问题...查询问题符合条件加入

$query4 = 'SELECT u.*, SUM(c.ts) AS total_sum1, SUM(r.bv) AS total_sum 
FROM users u 
LEFT JOIN 
(SELECT user_id ,SUM(points) AS ts FROM coupon GROUP BY user_id) c 
ON u.user_id=c.user_id AND u.user_id="'.$_SESSION['user_name'].'" 
LEFT JOIN 
(SELECT user_id ,SUM(basket_value) AS bv FROM retailer GROUP BY user_id) r 
ON u.user_id=r.user_id 
GROUP BY u.user_id'; 

我的问题是AND u.user_id="'.$_SESSION['user_name'].'"

我需要找到这个特定用户的积分.. 我在做错了吗?我的意思是,我知道我是,但什么? 感谢

回答

1

写这样的查询

$query4 = 'SELECT u.*, SUM(c.ts) AS total_sum1, SUM(r.bv) AS total_sum 
FROM users u 
LEFT JOIN 
(SELECT user_id ,SUM(points) AS ts FROM coupon GROUP BY user_id) c 
ON u.user_id=c.user_id 
LEFT JOIN 
(SELECT user_id ,SUM(basket_value) AS bv FROM retailer GROUP BY user_id) r 
ON u.user_id=r.user_id 
where u.user_id="'.$_SESSION['user_name'].'" 
GROUP BY u.user_id'; 
+0

这工作就像一个魅力:) –

+0

@al_alb欢迎.. :) –