操纵有序散列红宝石1.8.7

Question

我有一个返回有序散列

counts = VideoLog.count(
    :conditions =>["question_id = ? AND user_id = ? AND created_at >= ? AND created_at <= ? AND dashboard = ? AND watched = ?", video.id,current_user.id, @start_date, @end_date, "#{@dashboard}", 1], 
    :group  => "created_at" 
) 

计数下面的查询是一个有序的哈希：

{Wed Nov 30 07:37:36 UTC 2011=>1, Fri Nov 18 11:01:05 UTC 2011=>1, Wed Nov 30 07:38:16 UTC 2011=>1} 

，我想修改它的索引到具体的时区，然后将它们转换为日期，然后遍历它们，我该怎么做？

Answer 1

你没有指定你想用重复的键做什么，我假设你想对它们进行求和。所以：

h = {"Wed Nov 30 07:37:36 UTC 2011"=>1, "Fri Nov 18 11:01:05 UTC 2011"=>1, "Wed Nov 30 07:38:16 UTC 2011"=>1} 

h.inject(Hash.new 0) do |res, pair| 
    res[Time.parse(pair.first).in_time_zone("Europe/Paris").to_date] += pair.last; res 
end 

，其结果是

=> {Wed, 30 Nov 2011=>2, Fri, 18 Nov 2011=>1} 

Answer 2

像这样将工作：

counts.each do |key,value| 
    key = Date.parse key.localtime("+12:00").to_s 
    # do something 
end