2012-05-21 84 views
0

我已经添加了一个UpdatePanel环绕一个GridView并给它两个触发器,它们是UpdatePanel之外的按钮。我无法获得按钮单击事件来触发GridView异步刷新。ASP.NET UpdatePanel不工作

我敢肯定,数据源正在更新,因为F5刷新页面显示新的数据(这是通过文本框提交)

我也试过编程更新在代码隐藏文件中UpdatePanelUpdatePanel1.Update(); )但是也不这样做。

这里是我的代码:

<%@ Page Language="C#" MasterPageFile="~/MasterPage.master" AutoEventWireup="true" 
    CodeFile="GamePage.aspx.cs" Inherits="GamePage" %> 

<asp:Content ID="Content1" ContentPlaceHolderID="head" runat="Server"> 
</asp:Content> 
<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="Server"> 
    <asp:ScriptManager ID="ScriptManager1" runat="server"> 
    </asp:ScriptManager> 
    <span id="userGuess"> 
     <asp:Label ID="gameStatusLabel" runat="server" CssClass="guesses" Text="15"> 
     </asp:Label> 
     <asp:Label ID="guessLabel" runat="server" Text="Enter your guess:" 
      CssClass="guessLabel"></asp:Label> 
     <asp:TextBox ID="GuessTxtBx" runat="server" MaxLength="4"></asp:TextBox> 
     <asp:RequiredFieldValidator ID="RequiredFieldValidator1" runat="server" 
      ControlToValidate="GuessTxtBx" 
      ErrorMessage="Don't forget to guess!" CssClass="error" Visible="True" 
      Display="Dynamic"></asp:RequiredFieldValidator> 
     <asp:RegularExpressionValidator ID="RegularExpressionValidator1" runat="server" 
      ControlToValidate="GuessTxtBx" 
      ErrorMessage="Your guess must be a four digit number" 
      ValidationExpression="\d{4}" 
      CssClass="error" Visible="True" Display="Dynamic"></asp:RegularExpressionValidator> 
     <span class="guessBtns"> 
      <asp:Button ID="SubmitBtn" runat="server" OnClick="SubmitBtn_Click" 
       Text="Submit Guess"/> 
      <asp:Button ID="newGameButton" runat="server" OnClick="newGameButton_Click" 
       Text="New Game" /></span> 
    </span> 
    <div> 
     The game history:<br /> 
     <br /> 
     <asp:UpdatePanel ID="UpdatePanel1" runat="server" ChildrenAsTriggers="false" 
       UpdateMode="Conditional"> 
      <ContentTemplate> 
       <asp:GridView ID="TurnGridView" runat="server" AutoGenerateColumns="False" 
        DataKeyNames="turnID" 
        DataSourceID="TurnsDataSource1" Height="133px" Width="446px" 
         CssClass="table3"> 
        <Columns> 
         <asp:BoundField DataField="turnID" HeaderText="turnID" 
          InsertVisible="False" ReadOnly="True" 
          SortExpression="turnID" Visible="False" /> 
         <asp:BoundField DataField="gameID" HeaderText="gameID" 
          SortExpression="gameID" Visible="False" /> 
         <asp:BoundField DataField="guess" HeaderText="Your Guess" 
          SortExpression="guess" /> 
         <asp:BoundField DataField="responseBulls" HeaderText="Bulls" 
          SortExpression="responseBulls" /> 
         <asp:BoundField DataField="responseCows" HeaderText="Cows" 
          SortExpression="responseCows" /> 
        </Columns> 
       </asp:GridView> 
       <asp:ObjectDataSource ID="TurnsDataSource1" runat="server" 
        SelectMethod="GetTurnsByGameID" 
        TypeName="BusinessTier.Turn" 
        OldValuesParameterFormatString="original_{0}" 
        onselecting="TurnsDataSource1_Selecting"> 
        <SelectParameters> 
         <asp:Parameter Name="gameID" Type="Int32" /> 
        </SelectParameters> 
       </asp:ObjectDataSource> 
      </ContentTemplate> 
      <Triggers> 
       <asp:AsyncPostBackTrigger ControlID="SubmitBtn" EventName="Click"/> 
       <asp:AsyncPostBackTrigger ControlID="newGameButton" EventName="Click" /> 
      </Triggers> 
     </asp:UpdatePanel> 
    </div> 
</asp:Content> 
+0

看看这可以帮助你:触发在UpdatePanel的更新通过控制​​是在不同的ContentTemplate(http://stackoverflow.com/questions/417131/trigger-an-update-of-the- updatepanel-by-a-control-that-is-in-different-contentpl) – jadarnel27

+0

感谢您的参考,但我无法完全理解它。总结;我有一个GridView在文本框中显示以前的条目。我希望submitBtn触发两个数据被发送到Gridview的数据源,同时也是Girdview的异步更新。 为了确保被迟添加触发器尽可能(根据您的链接)我加入他们,当文本框被改变。这不知何故仍然无法工作。无论如何,尽管 – hippo30

+0

首先确定是否有任何错误。对于例如有时候这将是由于没有正确关闭html标签。 –

回答

1

你可能得到的是被吞了服务器端错误。要查看错误消息,最简单的方法是将AsyncPostBackTrigger临时替换PostBackTrigger

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