搜索在阵列

Question

我想通过数组搜索一个具体项目：

letters = ["a", "b", "c", "d", "e"] 

，看是否"b"是它;如果是，那么它应该说是的。我的理解：

letters[0..0] == ["a"] 

我尝试这样做：

if letters[0..5] == ["b"] 
    puts "Yes, the letter 'b' in there." 
else 
    puts "No 'b' in the array." 
end 

Answer 1

if letters.index('b') 
    puts "yes" 
else 
    puts "no" 
end 

Answer 2

有一个在建造方法，这样做：

letters.include? "b" 

Answer 3

尝试：http://www.ruby-doc.org/core-2.1.3/Array.html#method-i-include-3F

if letters.include?("b") 
    puts "Yes, the letter 'b' in there." 
else 
    puts "No 'b' in the array." 
end