将图像从tableView传递到Swift中的viewController

我在Assets文件夹中有图像，并且Im试图将数据从tableView传递到下一个viewController.I有两个表格，我创建了UIImageView的出口。
ThirdView.swift包含结构
进口的UIKit将图像从tableView传递到Swift中的viewController

struct ThirdView { 
var ThirdViewArray = [String]() 
var Pic = [String]() 
}

SecondTableViewController.swift包含

class SecondTableViewController: UITableViewController { 

var ExerciseListArray = [String]() 
var SecondAnswerArray = [String]() 



override func viewDidLoad() { 
    super.viewDidLoad() 
} 
override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int { 
    return ExerciseListArray.count 
} 
override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell { 
    var Cell = self.tableView.dequeueReusableCell(withIdentifier: "SecondCell", for: indexPath) as UITableViewCell 
    Cell.textLabel?.text = ExerciseListArray[indexPath.row] 

    return Cell 
} 

override func prepare(for segue: UIStoryboardSegue, sender: Any?) { 
    var indexPath: NSIndexPath = self.tableView.indexPathForSelectedRow! as NSIndexPath 
    var DestViewController = segue.destination as! ExercisesViewController 
    DestViewController.FirstString = SecondAnswerArray[indexPath.row] 
    DestViewController.ExerciseImage = SecondAnswerArray[indexPath.row] 
} 


}

然而，SecondAnswerArray是String类型的，我得到一个错误：
“不能赋值类型为UIImage的字符串“上线DestViewController.ExerciseImage = SecondAnswerArray [indexPath.row]
最后，FirstTableViewControl ler.swift：类FirstTableViewController：{的UITableViewController

var BodyPartsArray = [String]() 
var SecondArray = [SecondTable]() 
var ThirdArray = [ThirdView]() 

override func viewDidLoad() { 
    super.viewDidLoad() 
    // Do any additional setup after loading the view, typically from a nib. 
    BodyPartsArray = ["Neck", "Shoulders", "Upper Arms", "Forearms", "Back", "Chest", "Waist", "Hips", "Thighs", "Calves"] 

    SecondArray = [ 
    SecondTable(SecondTitle: ["Neck1","Neck2","Neck3"]), 
    SecondTable(SecondTitle: ["Shoulders1","Shoulders2","Shoulders3"]), 
    SecondTable(SecondTitle: ["Upper Arms1","Upper Arms2","Upper Arms3"]), 
    SecondTable(SecondTitle: ["Forearms1","Forearms2","Forearms3"]), 
    SecondTable(SecondTitle: ["Back1","Back2","Back3"]), 
    SecondTable(SecondTitle: ["Chest1","Chest2","Chest3"]), 
    SecondTable(SecondTitle: ["Waist1","Waist2","Waist3"]), 
    SecondTable(SecondTitle: ["Hips1","Hips2","Hips3"]), 
    SecondTable(SecondTitle: ["Thighs1","Thighs2","Thighs3"]), 
    SecondTable(SecondTitle: ["Calves1","Calves2","Calves3"])] 

    ThirdArray = [ 
     ThirdView(ThirdViewArray: ["NeckText1","NeckText2","NeckText3"], Pic: []), 
     ThirdView(ThirdViewArray: ["ShouldersText1","ShouldersText2","ShouldersText3"], Pic: ["310","311","312"]), 
     ThirdView(ThirdViewArray: ["Upper ArmsText1","Upper ArmsText2","Upper ArmsText3"], Pic: ["313","314","315"]), 
     ThirdView(ThirdViewArray: ["ForearmsText1","ForearmsText2","ForearmsText3"], Pic: ["","",""]), 
     ThirdView(ThirdViewArray: ["BackText1","BackText2","BackText3"], Pic: ["","",""]), 
     ThirdView(ThirdViewArray: ["ChestText1","ChestText2","ChestText3"], Pic: ["","",""]), 
     ThirdView(ThirdViewArray: ["WaistText1","WaistText2","WaistText3"], Pic: ["","",""]), 
     ThirdView(ThirdViewArray: ["HipsText1","HipsText2","HipsText3"], Pic: ["","",""]), 
     ThirdView(ThirdViewArray: ["ThighsText1","ThighsText2","ThighsText3"], Pic: ["","",""]), 
     ThirdView(ThirdViewArray: ["CalvesText1","CalvesText2","CalvesText3"], Pic: ["","",""])] 
} 

override func didReceiveMemoryWarning() { 
    super.didReceiveMemoryWarning() 
    // Dispose of any resources that can be recreated. 
} 
override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int { 
    return BodyPartsArray.count 
} 

override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell { 
    let Cell = self.tableView.dequeueReusableCell(withIdentifier: "Cell", for: indexPath) as UITableViewCell 
    Cell.textLabel?.text = BodyPartsArray[indexPath.row] 

    return Cell 
} 

override func prepare(for segue: UIStoryboardSegue, sender: Any?) { 

    let indexPath: NSIndexPath = self.tableView.indexPathForSelectedRow! as NSIndexPath 
    let DestViewController = segue.destination as! SecondTableViewController 
    var SecondTableArrayTwo: SecondTable 
    SecondTableArrayTwo = SecondArray[indexPath.row] 
    DestViewController.ExerciseListArray = SecondTableArrayTwo.SecondTitle 


    var ThirdAnswerArray: ThirdView 
    ThirdAnswerArray = ThirdArray[indexPath.row] 
    DestViewController.SecondAnswerArray = ThirdAnswerArray.ThirdViewArray 
    DestViewController.SecondAnswerArray = ThirdAnswerArray.Pic 
} 

}

再次，我上了线DestViewController.SecondAnswerArray = ThirdAnswerArray.Pic

ExercisesViewController了同样的错误：
进口的UIKit

类ExercisesViewController：UIViewController {

@IBOutlet weak var TextView: UITextView! 
@IBOutlet weak var ImageView: UIImageView! 

var FirstString = String() 
var ExerciseImage = String() 

override func viewDidLoad() { 

    TextView.text = FirstString 
    ImageView.image = ExerciseImage 

} 
}

任何人都可以帮助我解决这个错误，也显示我的资产加载图片到FirstTableViewController.swift ThirdArray的我的UIImageView的正确方法？
谢谢

来源

2016-12-26 lukas28277

将是很好，如果你可以分享ExercisesViewController的代码有更好的建议，但是这可能会帮助您：

首先，变量DestViewController.ExerciseImage in ExercisesViewController可能是类型UIImage，在您的阵列上SecondAnswerArray您包含Strin类型的对象G。如下声明：

var SecondAnswerArray = [String]()

当您从SecondAnswerArray值分配给预期为的UIImage一个对象，你会得到错误说

Cannot assign value of type String to type UIImage"

变化的类型ExercisesViewController.ExerciseImage是类型字符串这将解决您的第一个问题。

要从资源文件夹设置图像您简单指定一个图像文件名到的UIImage，如：

let img = UIImage(named: "NAME_OF_YOUR_FILE_WITHOUT_EXTENSION")

那么图像设置为的UIImageView

imageView.image = img

希望这有助于

来源

2016-12-26 20:27:24 Shachar

感谢您的回复，我已将ExercisesViewController添加到我的原始问题。我已经改变了ExerciseImage并且将Pic改成了String，并且错误消失了。但是，因为ExerciseImage现在是String类型，而ImageView是UIImageView类型，所以现在我得到相同的错误。我应该将IBOutlet类型更改为anyObject吗？ – lukas28277

否的ImageView应保持一个UIImageView，但你应该用你的String对象发起一个UIImage，然后将其分配给您的图像视图像这样： imageView.image =的UIImage（命名为：ExerciseImage）这是假设你ExerciseImage是您尝试加载的图像文件的名称。如果答案对您有帮助，请将其标记为正确。 – Shachar

Cannot assign value of type String to type UIImage" on the line DestViewController.ExerciseImage = SecondAnswerArray[indexPath.row]

错误信息告诉你一切。 ExerciseImage是UIImage的类型，您正在为其分配字符串。

首先创建UIImage对象比它分配给ExerciseImage

let image = UIImage(named: SecondAnswerArray[indexPath.row]) 
DestViewController.ExerciseImage = image

来源

2016-12-26 19:16:40 Sahil

将图像从tableView传递到Swift中的viewController

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