努力检查连续数据条目的逻辑

Question

我想弄清楚如何处理今天早上我发现自己的一个棘手的小局面。我在我的数据库中有一个条目表，用于存储有关用户每月条目的详细信息（信息捕获的东西） - 我想每月增加一个月的数量（不是ID）。这个想法是使用“数字”字段能够识别连续的每月条目并且忽略彼此靠近的条目。

当用户访问网站开始一个新的条目时，我检查最后一个条目的日期是否超过21天前（它符合有效月份），然后我将“数字“为这个新的条目。问题是，我最终可能会得到一系列间隔不足21天的记录（因此所有记录都有相同的记录），但这些记录共同超过21天！我需要能够找到一些逻辑来处理这个问题 - 任何人有任何想法？

下面是一个存储数据的例子，以及我遇到的问题。

+------+--------+------------+------------+----------------------------+ 
| id | number | initiated | updated | last_category_reached  | 
+------+--------+------------+------------+----------------------------+ 
| 4 |  1 | 1277914181 | 1277914320 | complete     | 
| 105 |  2 | 1282639343 | 1283444717 | complete     | 
| 397 |  3 | 1284999429 | 1285001298 | complete     | 
| 404 |  3 | 1287478550 | 1287478631 | complete     | 
| 636 |  3 | 1287479243 | 1287479377 | complete     | 
| 649 |  3 | 1287581361 | 1287581466 | complete     | 
| 652 |  3 | 1287585123 | 1287585365 | complete     | 
| 656 |  3 | 1290185205 | 1290424128 | complete     | 
| 1105 |  3 | 1292421193 | 1292426686 | complete     | 
| 1106 |  3 | 1292426769 | 1292426870 | complete     | 
+------+--------+------------+------------+----------------------------+ 

我的PHP逻辑低于...

public function update_entry($stage = NULL) 
    { 
     // Get last number entered for this user 
     $last_entry = $this->last_entry(); 

     // If part one, user profile is calling the update (passing the next stage as a param) 
     if ($stage === 'user/profile/2?s=p_prof&p=2') 
     { 
      // Only at this stage do we ever create a new entry 
      $entry = ORM::factory('data_entry'); 

      // If no previous sessions, start from 1 
      if ($last_entry === FALSE) 
       $num = 1; 

      //Here we need to check the time period elapsed since the last submission 
      else 
      { 
       // Check if time difference between last visit and current time is less than 49 days and more than 21 days 
       if (($last_entry->initiated > time() - 4233600) && ($last_entry->initiated < time() - 1814400)) 
       { 
        // Within allowed timeframe, ok to increment by one as a new entry 
        $num = $last_entry->number + 1; 
       } 
       // More than 49 days since last visit 
       elseif (($last_entry->initiated < time() - 4233600)) 
       { 
        // Increment by two to break consecutive entries 
        $num = $last_entry->number + 2; 
       } 
       // Entry is within the last 21 days - if user never finished stages, use last entry created instead of creating a new one 
       else 
       { 
        // If they are back at the start having completed a full entry the last time, ok to create a new entry - otherwise use the one created the last time 
        if ($last_entry->last_category_reached !== 'complete') 
         $entry = $last_entry; 

        $num = $last_entry->number; 
       } 

      } 

      // Save the rest of the data for a new entry 
      $entry->number = $num; 
      $entry->initiated = time(); 
      $entry->updated = time(); 
      $entry->last_category_reached = $stage; 
      $entry->user_id = $this->id; 
      $entry->save(); 
     } 
     // If it's been more than 49 days since last part completion of an entry, user won't be given option to finish the entry, so no need for time check here 
     elseif ($stage !== NULL) 
     { 
      // This must be a continuation of a form, not the beginning of a new one 
      // Just update the stage reached and save 
      $last_entry->last_category_reached = $stage; 
      $last_entry->updated = time(); 
      $last_entry->save(); 
      // Assign to $entry for return 
      $entry = $last_entry; 
     } 

     return $entry; 
    } 

    /** 
    * Returns the the last data entry session 
    * @return 
    */ 
    public function last_entry() 
    { 
      return $this 
        ->limit(1) 
        ->data_entries 
        ->current(); 
    } 

Answer 1

我会在伪代码做什么：

如果有以前的数量，采取与最大的条目（数量）和min（id）。 计算此条目与当前时间之间的延迟时间。 如果小于21天，我不更改数字，如果更多，我更改数字。

如果您应用此选项，则不会获得超过21天的期限。