好吧,我想我只是设置我的MySQL表很差。我身份证,其他的东西,并不重要,然后,movielink1,movielink2,movielink3,movielink4,movielink5输出多个记录php
我想要一个按钮出现每一个,只有如果movielink#存在。他们大多数只有movielink1填充。
我想我只是看着它错误的方式。这是我的代码。
<?php
$data2 = mysql_query("SELECT movielink1,movielink2,movielink3,movielink4,movielink5 FROM movies WHERE id=$id");
if (mysql_num_rows($data2) > 0) {
while($info2 = mysql_fetch_array($data2)) {
Print '<a href="'.$info['movielink1'];.'?iframe=true&width=100%&height=100%" rel="prettyPhoto[iframes]" title="'.$info['title'];.'"><img src="http://tipmypicks.com/cssmovie/images/watchmovie.png" class="watchmovie"></a>';
}
} else {
Print 'Error!';
}
?>
感谢的建议,我只是说这一点,但它仍然无法正常工作,也不是接近它的好方法。
$data1 = mysql_query("SELECT movielink1 FROM movies WHERE id=$id");
if (mysql_num_rows($data1) > 0) {
while($info1 = mysql_fetch_array($data1)) {
Print '<a href="'.$info['movielink1'].'?iframe=true&width=100%&height=100%" rel="prettyPhoto[iframes]" title="'.$info['title'].'"><img src="http://tipmypicks.com/cssmovie/images/watchmovie.png" class="watchmovie"></a>';
}
} else {
}
$data2 = mysql_query("SELECT movielink2 FROM movies WHERE id=$id");
if (mysql_num_rows($data2) > 0) {
while($info2 = mysql_fetch_array($data2)) {
Print '<a href="'.$info['movielink2'].'?iframe=true&width=100%&height=100%" rel="prettyPhoto[iframes]" title="'.$info['title'].'"><img src="http://tipmypicks.com/cssmovie/images/watchmovie.png" class="watchmovie"></a>';
}
} else {
}
$data3 = mysql_query("SELECT movielink3 FROM movies WHERE id=$id");
if (mysql_num_rows($data3) > 0) {
while($info3 = mysql_fetch_array($data3)) {
Print '<a href="'.$info['movielink3'].'?iframe=true&width=100%&height=100%" rel="prettyPhoto[iframes]" title="'.$info['title'].'"><img src="http://tipmypicks.com/cssmovie/images/watchmovie.png" class="watchmovie"></a>';
}
} else {
}
$data4 = mysql_query("SELECT movielink4 FROM movies WHERE id=$id");
if (mysql_num_rows($data4) > 0) {
while($info4 = mysql_fetch_array($data4)) {
Print '<a href="'.$info['movielink4'].'?iframe=true&width=100%&height=100%" rel="prettyPhoto[iframes]" title="'.$info['title'].'"><img src="http://tipmypicks.com/cssmovie/images/watchmovie.png" class="watchmovie"></a>';
}
} else {
}
$data5 = mysql_query("SELECT movielink5 FROM movies WHERE id=$id");
if (mysql_num_rows($data5) > 0) {
while($info5 = mysql_fetch_array($data5)) {
Print '<a href="'.$info['movielink5'].'?iframe=true&width=100%&height=100%" rel="prettyPhoto[iframes]" title="'.$info['title'].'"><img src="http://tipmypicks.com/cssmovie/images/watchmovie.png" class="watchmovie"></a>';
}
} else {
}
尝试WHERE ID = '$ ID' –
'如果{这里呼应你的链接}'(空($ INFO2 [ 'movielink1'])!)。另外'打印'应该是[打印](http://www.php.net/print)*区分大小写* – bansi
'title'从哪里来? –