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我有以下函数递归检查数独拼图中的每个正方形以使其合法,并且在运行时我不断收到分段错误,因此我将cout检查放到了每个地方以查看它打破的位置。不知何故,它停留在循环中,并继续不断地调用addSquare函数,而没有结束。我如何让它停止?为什么我的循环在递归函数中无限?
bool DoTheWork::addSquare(int& depth)
{
depth++;
cout << depth << endl;
if(board.checkZeroes()==false){ //if the game is won, return true
cout << "ifstatement1" << endl;
return true;
}
else {
for(int i = 0; i < 10; i++) {
cout << "loop1" << endl;
for(int j = 0; j < 10; j++) {
cout << "loop2" << endl;
if(this->board.getSquare(i,j)==0) { //go through each
cout << "ifstatement2" << endl;
for(int k = 1; k < 10; k++) {
cout << "loop3" << endl;
//try each number in that square for legality
board.setSquare(i,j,k);
//set that square to the number you are currently on
if(board.isLegal()==false) {
cout << "ifstatement3" << endl;
board.unsetSquare(i,j);
}
//if the board is not legal for that number, unset that square
if(addSquare(depth)==true) {
cout << "ifstatement4" << endl;
return true;
}
//recursive function, if method is true then it will return true
board.unsetSquare(i,j);
}
}
}
}
}
return false;
} // bool DoTheWork::addSquare(int& depth)
当在终端中运行,它打印如下: 环1个 环2 ifstatement2 循环3 ifstatement3 LOOP1 ... 及以后,直到它说:“分割故障(核心转储)“
每次深度增加时,”ifstatement3“之后的数字增加1。
包括checkZeroes以下功能:
bool Board::checkZeroes()
{
bool zeroPresent = false;
//assume there are no zeroes, easier for coding
for(int i=0; i<9; i++) {
for(int j=0; j<9; j++) {
if(theBoard[i][j] == 0){
//go through each value of theBoard, if any are 0 return true
zeroPresent = true;
}
}
}
return zeroPresent;
} // int Board::checkZeroes()
我们需要足够的代码来复制问题。看到实际的输出也会有所帮助。 –
如果您遇到分段错误,“cout”可能不会被刷新。您可能看不到*整个*输出。 – zmbq
@zmbq他在每个'cout'语句中都有一个'endl',并且'endl'刷新。 –