在第一列之后写入csv文件的第二列

Question

我正在将我的代码的输出写入.csv文件。有三个目录，每个目录包含50个文件。我想将每个目录文件的输出写入不同的列。喜欢;

 group1 group2 group3 
file1 1445  89 87 
file2 1225  100 47 
file3 650  120 67 
file4 230  140 97 

我有下面的代码这样做，

from collections import Counter 
import glob 
import os 

out= open('output.csv','a') 
out.write (';''group-1') 
out.write (';''group-2') 
out.write (';''group-3') 
out.write('\n') 
i = 1 

while i<=50: 
out.write("file-%d" %i) 
out.write('\n') 
i+=1 
i=1 
path = 'group/group-*-files/*.txt' 

files=sorted(glob.glob(path)) 
c=Counter() 

for filename in files: 

for line in open(filename,'r'): 

    c.update(line.split()) 

for item in c.items(): 
    oi=("{}\t{}".format(*item)) 
    out_array = oi.split() 

    if out_array[0]=='00000000': 

    out.write(out_array[1]) 
    out.write('\n') 
    c.clear() 

我越来越并没有能够解决的问题，答案开始后，文件编号写在第一列50

file48 
file49 
file50 
1445 
1225 
.. 

我想写第一组50列，第二组50列，第三组最后50列

最终输出的样子，

group1 group2 group3 
file1 145  89  87 
file2 850  100 47 
file3 650  120 67 
file4 230  140 97 

Answer 1

这是我怎么会重写代码。我所做的更改：

• 打开文件时，使用with语句，以确保他们得到关闭
• 使用csv模块，使编写csv文件更容易
• 写一次通过建立整条生产线在将其写入文件之前，一次一行。

因为我不知道你的文件是什么，所以没有经过彻底的测试。

import csv 
from collections import Counter 
import glob 
import os 

with open('output.csv','a') as out: 
    writer =csv.writer(out, delimiter='\t') 
    writer.writerow(['']+['group{}'.format(i) for i in range(1, 4)]) 
    path = 'group/group-*-files/*.txt' 

    files=sorted(glob.glob(path)) 
    c=Counter() 
    for i, filename in enumerate(files): 
     line = ['file-{}'.format(i)] 
     with open(filename) as infile: 
      for line in infile: 
       c.update(line.split()) 
     for key, count in c.items(): 
      if key == '00000000': 
       line.append(count) 
     writer.writerow(line) 
     c.clear() 

Answer 2

您至少有一个问题与错误压痕。您首先通过以下方式生成所有文件名：

... 
while i<=50: 
out.write("file-%d" %i) 
out.write('\n')    # replace \n to column delimiter \t 
i+=1 

然后开始处理文件。你删除这一行i=1和所有其他文本必须有相同的缩进开始为out.write

from collections import Counter 
import glob 
import os 

out= open('output.csv','a') # flag a - Do you want append to existing file ? 
out.write('file;group-1;group2;group3') # You forget column 1 - filename 
# out.write (';''group-1') 
# out.write (';''group-2') 
# out.write (';''group-3') 
# out.write('\n') 
i = 1 
while i<=50: 
out.write("file-%d" %i) 
# out.write('\n') 
out.write(';') # Insert character for column delimiter 
i+=1 
# i=1 Delete, because will cause infinite loop 
# Following code must run inside while loop, indent to the same level 
# as previous lines 
path = 'group/group-*-files/*.txt' 

files=sorted(glob.glob(path)) 
c=Counter() 

for filename in files: 

    for line in open(filename,'r'): 

    c.update(line.split()) 

    for item in c.items(): 
    oi=("{}\t{}".format(*item)) 
    out_array = oi.split() 

    if out_array[0]=='00000000': 

    out.write(out_array[1]) 
    # out.write('\n') - You don want create new lines, but only new columns for every group 
    out.write(';') 

    c.clear() 
    out.write('\n') # New line - new record