嗨,大家好,我想知道你们中的任何一个人是否尝试过使用3个相关的表格在laravel的表格中插入一条记录?例如Laravel插入3个相关表格
// Database Schema for Pharmacy
Schema::create('pharmacies', function (Blueprint $table) {
$table->increments('id');
$table->string('name');
$table->text('address');
});
// Relationship in App\Pharmacy table
public function pharmacists() {
return $this->hasMany('App\Pharmacist');
}
现在我有另一个表
Schema::create('pharmacists', function (Blueprint $table) {
$table->increments('id');
$table->integer('pharmacy_id')->unsigned()->index();
$table->foreign('pharmacy_id')->references('id')->on('pharmacies')->onDelete('cascade');
$table->string('fname');
});
// And this is the relationship in App\Pharmacist class
public function account() {
return $this->hasOne('App\Account');
}
public function pharmacy() {
return $this->belongsTo('App\Pharmacy');
}
现在第三台
// This contain the foreign key for pharmacist_id
Schema::create('accounts', function (Blueprint $table) {
$table->increments('id');
$table->integer('pharmacist_id')->unsigned()->index();
$table->foreign('pharmacist_id')->references('id')->on('pharmacists')->onDelete('cascade');
$table->string('username')->unique();
});
// This is the relationship in App\Account class
public function pharmacists() {
return $this->belongsTo('App\Pharmacist');
}
现在我试图AccountsController下
$input = Request::all();
$pharmacy = Pharmacy::create([
"name" => "Wendies Chicken",
"address" => "My Address",
]);
$pharmacists = new Pharmacist([
"fname" => "Administrator",
]);
$account = new Account([
"username" => "root",
]);
$pharmacists->account()->save($account);
$pharmacy->pharmacists()->save($pharmacists);
保存这个使用此代码但我收到了一封电子邮件恐怖说
Integrity constraint violation: 1048 Column 'pharmacist_id' cannot be null (SQL: insert into `accounts` (`username`, `pharmacist_id`, `updated_at`, `created_at`) values (root, 2015-08-09 05:13:31, 2015-08-09 05:13:31))
不知道如何保存这只是一个节省。我想保存3个相关表中的记录。有人可以帮我弄这个吗。由于
此问题解决了非常感谢,虽然我这样做,而不是$ pharmacy->药剂师() - >保存($药师) - >账户() - >保存($帐户);它似乎也起作用。谢谢你 –