2016-01-23 44 views
4

我有一个二维字符串由行分隔,每行内由值分隔。VBA解析2D分隔字符串到Excel中的范围内

所以这是一个以逗号分隔的字符串,每行末尾有一个EOL标记。例如:

val1, val2, val3 ... valn [EOL] 
val1, val2, val3 ... valn [EOL] 
... 
val1, val2, val3 ... valn [EOL] 

如果创建一个循环分裂()由[EOL]然后内部的另一个循环分裂()通过将各值的每一行“”,然后在一个时间到一个写每个值的一个单元格在工作表中它永远需要,所以我正在寻找一个更有效的解决方案。

是否可以将字符串解析为二维数组/变体,然后将整个事件一次写入指定范围?

+1

多个单元在技术上是2D阵列也因此可以用'UBound函数()'和'调整尺寸()'进入阵列分成范围的情况下直接循环。 –

回答

1

一种方法是首先在内存中组装一个数组,然后在一行代码中传输它。第一个函数MultiSplit假定每行包含相同数量的元素。第二个函数MultiSplit2放弃了这个假设(以更多处理为代价)。使用符合您的情况的版本。

Function MultiSplit(s As String, d1 As String, d2 As String) As Variant 
    'd1 is column delimiter, d2 is row delimiter 
    'returns an array 

    Dim m As Long, n As Long, i As Long, j As Long 
    Dim tempRows As Variant, tempRow As Variant 
    Dim retA As Variant 'return array 

    tempRows = Split(s, d2) 
    m = UBound(tempRows) 
    If Len(tempRows(m)) = 0 Then 'original string ends with a delimiter 
     m = m - 1 
     ReDim Preserve tempRows(m) 
    End If 

    tempRow = Split(tempRows(0), d1) 
    n = UBound(tempRow) 
    ReDim retA(1 To m + 1, 1 To n + 1) '1-based more natural for intended ranges 

    For i = 1 To m + 1 
     For j = 1 To n + 1 
      retA(i, j) = tempRow(j - 1) 
     Next j 
     If i < m + 1 Then tempRow = Split(tempRows(i - 1), d1) ' next row to process 
    Next i 
    MultiSplit = retA 
End Function 

Sub test() 
    Dim testString As String, A As Variant, R As Range 
    testString = "a,b,c,d;e,f,g,h;i,j,k,l" 

    A = MultiSplit(testString, ",", ";") 
    Set R = Range(Cells(1, 1), Cells(UBound(A, 1), UBound(A, 2))) 
    R.Value = A 
End Sub 

这里是一个可以处理各种长度的行版本:

Function MultiSplit2(s As String, d1 As String, d2 As String) As Variant 
    'd1 is column delimiter, d2 is row delimiter 
    'returns an array 

    Dim m As Long, n As Long, i As Long, j As Long 
    Dim tempRows As Variant, jaggedArray As Variant 
    Dim retA As Variant 'return array 

    tempRows = Split(s, d2) 
    m = UBound(tempRows) 
    If Len(tempRows(m)) = 0 Then 'original string ends with a delimiter 
     m = m - 1 
     ReDim Preserve tempRows(m) 
    End If 

    ReDim jaggedArray(0 To m) 
    For i = 0 To m 
     jaggedArray(i) = Split(tempRows(i), d1) 
     If UBound(jaggedArray(i)) > n Then n = UBound(jaggedArray(i)) 
    Next i 

    ReDim retA(1 To m + 1, 1 To n + 1) '1-based more natural for intended ranges 

    For i = 1 To m + 1 
     For j = 1 To 1 + UBound(jaggedArray(i - 1)) 
      retA(i, j) = jaggedArray(i - 1)(j - 1) 
     Next j 
    Next i 
    MultiSplit2 = retA 
End Function 

Sub test2() 
    Dim testString As String, A As Variant, R As Range 
    testString = "a,b,c;d,e,f,g,h;i;j,k,l,m,n,o,p;" 

    A = MultiSplit2(testString, ",", ";") 
    Set R = Range(Cells(1, 1), Cells(UBound(A, 1), UBound(A, 2))) 
    R.Value = A 
End Sub 

为了得到一些定时信息,我写了一子,以产生分裂成1000行的字符串和多达100列:

Sub test3() 
    Dim s As String, A As Variant, R As Range 
    Dim i As Long, j As Long, start As Double 
    Dim n As Long 

    For i = 1 To 1000 
     n = i Mod 100 
     For j = 1 To n 
      s = s & "a" & IIf(j < n, ",", vbCrLf) 
     Next j 
     DoEvents 'in case it hangs 
    Next i 
    Debug.Print "String has length " & Len(s) 
    start = Timer 
    A = MultiSplit2(s, ",", vbCrLf) 
    Set R = Range(Cells(1, 1), Cells(UBound(A, 1), UBound(A, 2))) 
    R.Value = A 
    Debug.Print "Finished in " & Timer - start & " seconds" 
End Sub 

当我运行它,我得到的输出:

String has length 99990 
Finished in 0.09375 seconds 
1

我们可以做@Macro Man在评论中所说的话。如果所有行都包含相同数量的逗号分隔值,那将很容易。如果不是,它会更复杂。但仍然可以解决。在一个范围

Option Base 0 

Sub test() 

sString = "val1, val2, val3 ... valn" & Chr(10) & "val1, val2 ... valn" & Chr(10) & "val1, val2, val3, val4 ... valn" & Chr(10) & "val1" & Chr(10) 

Dim aDataArray() As Variant 
Dim lLinesCount As Long 
Dim lValuesCount As Long 
Dim lMaxValuesCount As Long 

aLines = Split(sString, Chr(10)) 
lLinesCount = UBound(aLines) 
ReDim aDataArray(0 To lLinesCount, 0) 

For i = LBound(aLines) To UBound(aLines) 
    aValues = Split(aLines(i), ",") 
    lValuesCount = UBound(aValues) 
    If lValuesCount > lMaxValuesCount Then lMaxValuesCount = lValuesCount 
    ReDim Preserve aDataArray(0 To lLinesCount, 0 To lMaxValuesCount) 

    For j = LBound(aValues) To UBound(aValues) 
    aDataArray(i, j) = aValues(j) 
    Next 
Next 

With ActiveSheet 
    .Range("B2").Resize(lLinesCount + 1, lMaxValuesCount + 1).Value = aDataArray 
End With 

End Sub 
+0

谢谢大家。这就是诀窍! – doncooper