Spring-bound list中的Freemarker迭代

Question

我有一个List<String>受Spring ModelAttribute的约束。如何在Freemarker中迭代它？

我已经试过：

<#list ${modelattribute.listField} as thing > 
    <tr><td>${thing}</td></tr></#list> 
</#list> 

但是Freemarker的是：不要期望转义序列

Encountered "{" at line 108, column 43 in things/search.html. 
Was expecting one of: ... 

我应该如何引用此值？

Answer 1

你应该做这样的事情：

<#list modelattribute.listField as thing > 
    <tr><td>${thing}</td></tr></#list> 
</#list>