假设以下数据库设置:
╔════════════════════════════╗ ╔═════════════════════════════════╗
║ People ║ ║ Your DataTable Info ║
╠════╦═══════════════════════╣ ╠═══════════════╦═════════════════╣
║ ID ║ Name ║ ║ PeopleName ║ PeopleCallPhone ║
╠════╬═══════════════════════╣ ╠═══════════════╬═════════════════╣
║ 1 ║ "John Smith" ║ ║ "John Smith" ║ 123-456-7890 ║
║ 2 ║ "Jane Doe" ║ ║ "Jane Doe" ║ 234-567-8900 ║
║ 3 ║ "Foo Bar" ║ ║ "Foo Bar" ║ 345-678-9000 ║
║ 4 ║ "Justin Time" ║ ║ "Justin Time" ║ 456-789-0000 ║
║ 5 ║ "Imma Mann" ║ ║ "Imma Mann" ║ 567-890-0000 ║
╚════╩═══════════════════════╝ ╚═══════════════╩═════════════════╝
而且,让我们假设你的数据结构为:
List<People> people = GetPeopleFromDB();
DataTable table = GetDataTableInfoFromDB();
为了使DataTable
列"PeopleName"
与来自people
来源的DataGridViewComboBoxColumn
一致,您必须设置DataGridViewComboBoxColumn.DataPropertyName
。由于DataTable
列中的值匹配People.Name
,因此您必须在DataGridViewComboBoxColumn.ValueMember
上设置该属性。例如:
var col = new DataGridViewComboBoxColumn();
col.Name = "PeopleName";
col.DataPropertyName = "PeopleName"; // The DataTable column name.
col.HeaderText = "Name";
col.DataSource = people;
col.DisplayMember = "Name";
col.ValueMember = "Name"; // People.Property matching the DT column.
this.dataGridView1.Columns.Add(col);
this.dataGridView1.DataSource = table;
this.dataGridView1.Columns[1].HeaderText = "Phone";
结果:
关于你的第二个问题,找到每个项目的ID,同时通过各行循环,您首先要抢的源ComboBoxColumn。然后,您可以遍历每行并使用第一列中的值,查找源中相关ID的值。例如:
List<People> ppl = ((DataGridViewComboBoxColumn)this.dataGridView1.Columns[0]).DataSource as List<People>;
foreach (DataGridViewRow row in this.dataGridView1.Rows)
{
if (row.Index != this.dataGridView1.NewRowIndex)
{
var cell = row.Cells[0] as DataGridViewComboBoxCell;
People person = ppl.SingleOrDefault(p => p.Name == cell.Value.ToString());
if (person != null)
{
Console.WriteLine("{0} {1}, {2}", person.ID, person.Name, row.Cells[1].Value);
}
}
}
输出:
请澄清你的类型:'People.ID'是'int','People.Name'是'string','PeopleName'是'字符串(匹配'People.Name')和'PeopleCallPhone'是什么? – OhBeWise
有些字符串,与People类无关。 –