两个日期之间的c + +日期差异

我试图做一个函数，读取两个日期，并选择较大的一个，然后获得天差异。到目前为止，我尝试了很多，但有时候答案是不正确的。
我找不到问题所在。任何人都可以帮助我找到问题，并且/或者就如何调试这类问题提供一些建议？两个日期之间的c + +日期差异

#include <iostream> 
#include <string.h> 
#include < string> 
#include <cstdlib> 
#include <sstream> 
using namespace std; 
int period(string days1, string months1, string years1, string days2,string months2, string years2) 
{ 
int periodday, periodmonth, periodyear, periodindays, 
year1 = atof(years1.c_str()), month1 = atof(months1.c_str()), 
day1 = atof(days1.c_str()), year2 = atof(years2.c_str()), 
month2 = atof(months2.c_str()), day2 = atof(days2.c_str()); 
int biggeryear, smalleryear, biggermonth, smallermonth, biggerday, smallerday; 
if (year1 > year2) { 
    biggeryear = year1; 
    biggermonth = month1; 
    biggerday = day1; 
    smalleryear = year2; 
    smallermonth = month2; 
    smallerday = day2; 
    } 
else { 
    biggeryear = year2; 
    biggermonth = month2; 
    biggerday = day2; 
    smalleryear = year1; 
    smallermonth = month1; 
    smallerday = day1; 
} 
if (year1 == year2) { 
    if (month1 > month2) { 
     biggeryear = year1; 
     biggermonth = month1; 
     biggerday = day1; 
     smalleryear = year2; 
     smallermonth = month2; 
     smallerday = day2; 
    } 
    else { 
     biggeryear = year2; 
     biggermonth = month2; 
     biggerday = day2; 
     smalleryear = year1; 
     smallermonth = month1; 
     smallerday = day1; 
    } 
    if (month1 == month2) { 
     if (day1 > day2) { 
      biggeryear = year1; 
      biggermonth = month1; 
      biggerday = day1; 
      smalleryear = year2; 
      smallermonth = month2; 
      smallerday = day2; 
     } 
     else { 
      biggeryear = year2; 
      biggermonth = month2; 
      biggerday = day2; 
      smalleryear = year1; 
      smallermonth = month1; 
      smallerday = day1; 
     } 
    } 
} 
periodday = biggerday - smallerday; 
periodmonth = biggermonth - smallermonth; 
periodyear = biggeryear - smalleryear; 
if (periodday < 0) { 
    periodmonth = periodmonth - 1; 
    if (biggermonth == 1 || biggermonth == 3 || biggermonth == 5 || 
    biggermonth == 7 || biggermonth == 8 | biggermonth == 12 || 
    biggermonth == 10) { 
     periodday += 31; 
    } 
    if (biggermonth == 4 || biggermonth == 6 || biggermonth == 9 || 
    biggermonth == 11) { 
     periodday += 30; 
    } 
    if (biggermonth == 2 && biggeryear == 0) { 
     periodday += 28; 
    } 
    if (biggermonth == 1 && biggeryear % 4 != 0) { 
     periodday += 29; 
    } 
} 
if (periodmonth < 0) { 
    periodyear--; 
    if (biggermonth == 1 || biggermonth == 3 || biggermonth == 5 || 
    smallermonth == 7 || biggermonth == 8 || biggermonth == 12 || 
    biggermonth == 10) 
    { 
     periodmonth = periodmonth + 12; 
     periodmonth = abs(periodmonth) * 31; 
    } 
    if (biggermonth == 4 || biggermonth == 6 || biggermonth == 9 || 
    biggermonth == 11) { 
     periodmonth = periodmonth + 12; 
     periodmonth = abs(periodmonth) * 30; 
    } 
    if (biggermonth == 2 && biggeryear % 4 == 0) { 
     periodmonth = periodmonth + 12; 
     periodmonth = abs(periodmonth) * 28; 
    } 
    if (biggermonth == 2 && biggeryear % 4 != 0) { 
     periodmonth = periodmonth + 12; 
     periodmonth = abs(periodmonth) * 29; 
    } 
} 
else if (periodmonth >= 0) { 
    if (biggermonth == 1 || biggermonth == 3 || biggermonth == 5 || 
    biggermonth == 7 || biggermonth == 8 || biggermonth == 12 || 
    biggermonth == 10) { 
     periodmonth = periodmonth * 31; 
    } 
    if (biggermonth == 4 || biggermonth == 6 || biggermonth == 9 || 
    biggermonth == 11) { 
     periodmonth = periodmonth * 30; 
    } 
    if (biggermonth == 2 && biggeryear % 4 == 0) { 
     periodmonth = periodmonth * 28; 
    } 
    if (biggermonth == 2 && biggeryear % 4 != 0) { 
     periodmonth = periodmonth * 29; 
    } 
} 
if (periodyear < 0) { 
    if (year1 % 4 != 0 || year2 % 4 != 0) { 
     periodyear = year2 - year1; 
     periodyear *= 366; 
    } 
    else { 
     periodyear = year2 - year1; 
     periodyear *= 365; 
    } 
} 
else if (periodyear >= 0) { 
    if (year1 % 4 != 0 || year2 % 4 != 0) { 
     periodyear *= 366; 
    } 
    else { 
     periodyear *= 365; 
    } 
} 
periodindays = periodday + periodmonth + periodyear; 
return abs(periodindays); 
} 
int main() 
{ 
    string daya = ("1"), montha = ("1"), yeara = ("2016"), yearb = ("2016"), 
    monthb = ("4"), dayb = ("27"); 
    int difference; 
    difference = period(daya, montha, yeara, dayb, monthb, yearb); 
    cout << difference << endl; 
    system("pause"); 
    return 0; 
}

来源

2016-04-27 abanoub maher

这听起来像你可能需要学习如何使用调试器来遍历代码。使用一个好的调试器，您可以逐行执行您的程序，并查看它与您期望的偏离的位置。如果你打算做任何编程，这是一个重要的工具。进一步阅读：** [如何调试小程序]（http://ericlippert.com/2014/03/05/how-to-debug-small-programs/）** – NathanOliver

编辑您的文章以获得正确的缩进 - 或者甚至没有人会在你的网站上认真对待大声笑。如果你这样做，我可以看看发生了什么。 – 2016-04-27 16:43:50

添加其失败并为其传递的输入。 –

我认为你做的事情有点复杂。我的建议是通过在struct tm中设置适当的字段并使用mktime（）来将日期转换为time_t值。然后，您可以使用difftime（）来计算两个日期之间的差值（以秒为单位）。

来源

2016-05-02 05:25:52

两个日期之间的c + +日期差异

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