我的回报应该是什么？

Question

我正在使用Python解析来自SOAP Web服务的XML响应。如下所示，Customer返回约40个值。我想知道是否有办法做到这一点，所以我只需在我的return声明中输入一项内容并获取所有返回的值？我试图使用for customer in doc.findall('.//Customer').itervalues()，并且这不起作用，因为我相信该调用是用于字典。 .iteritems背后的结果和推理结果相同。

doc = ET.fromstring(response_xml) 
for customer in doc.findall('.//Customer'): 
    customer_number = customer.findtext('CustomerNumber') 
    customer_first_name = customer.findtext('FirstName') 
    customer_last_name = customer.findtext('LastName') 
    customer_middle_name = customer.findtext('MiddleName') 
    customer_salutation = customer.findtext('Salutation') 
    customer_gender = customer.findtext('Gender') 
    customer_language = customer.findtext('Language') 
    customer_address1 = customer.findtext('Address1') 
    customer_address2 = customer.findtext('Address2') 
    customer_address3 = customer.findtext('Address3') 
    customer_city = customer.findtext('City') 
    customer_county = customer.findtext('County') 
    customer_state_code = customer.findtext('StateCode') 
    customer_zip_code = customer.findtext('ZipCode') 
    customer_phone_number = customer.findtext('PhoneNumber') 
    customer_business_phone = customer.findtext('BusinessPhone') 
    customer_business_ext = customer.findtext('BusinessExt') 
    customer_fax_number = customer.findtext('FaxNumber') 
    customer_birth_date = customer.findtext('BirthDate') 
    customer_drivers_license = customer.findtext('DriversLicense') 
    customer_contact = customer.findtext('Contact') 
    customer_preferred_contact = customer.findtext('PreferredContact') 
    customer_mail_code = customer.findtext('MailCode') 
    customer_tax_exempt_Number = customer.findtext('TaxExmptNumber') 
    customer_assigned_salesperson = customer.findtext('AssignedSalesperson') 
    customer_type = customer.findtext('CustomerType') 
    customer_preferred_phone = customer.findtext('PreferredPhone') 
    customer_cell_phone = customer.findtext('CellPhone') 
    customer_page_phone = customer.findtext('PagePhone') 
    customer_other_phone = customer.findtext('OtherPhone') 
    customer_other_phone_desc = customer.findtext('OtherPhoneDesc') 
    customer_email1 = customer.findtext('Email1') 
    customer_email2 = customer.findtext('Email2') 
    customer_optional_field = customer.findtext('OptionalField') 
    customer_allow_contact_postal = customer.findtext('AllowContactByPostal') 
    customer_allow_contact_phone = customer.findtext('AllowContactByPhone') 
    customer_allow_contact_email = customer.findtext('AllowContactByEmail') 
    customer_business_phone_ext = customer.findtext('BusinessPhoneExtension') 
    customer_internatinol_bus_phone = customer.findtext('InternationalBusinessPhone') 
    customer_international_cell = customer.findtext('InternationalCellPhone') 
    customer_external_x_reference_key = customer.findtext('ExternalCrossReferenceKey') 
    customer_international_fax = customer.findtext('InternationalFaxNumber') 
    customer_international_other_phone = customer.findtext('InternationalOtherPhone') 
    customer_international_home_phone = customer.findtext('InternationalHomePhone') 
    customer_preferred_name = customer.findtext('CustomerPreferredName') 
    customer_international_pager = customer.findtext('InternationalPagerPhone') 
    customer_preferred_lang = customer.findtext('PreferredLanguage') 
    customer_last_change_date = customer.findtext('LastChangeDate') 
    customer_vehicles = customer.findtext('Vehicles') 
    customer_ccid = customer.findtext('CCID') 
    customer_cccd = customer.findtext('CCCD') 


webservice.close() 
return 

Answer 1

我会写，作为一个发电机功能产生类型的字典其中关键的findtext参数匹配，如：

fields = ['CustomerNumber', 'FirstName', 'LastName', 
      # ... 
     ] 
for customer in doc.findall('.//Customer'): 
    yield dict((f, customer.findtext(f)) for f in fields) 

Answer 2

要么你想回到dict的list一个S：

customers = [] 
for customer in doc.findall('.//Customer'): 
    customer_dict = {} 
    customer_dict['number']  = customer.findtext('CustomerNumber') 
    customer_dict['first_name'] = customer.findtext('FirstName') 
    customer_dict['last_name'] = customer.findtext('LastName') 
    # ad nauseum 
    customers.append(customer_dict) 

webservice.close() 
return customers 

或者你做一个Customer类来处理这一点，并返回客户实例的list。

Answer 3

我会用词典的词典：

doc = ET.fromstring(response_xml) 
customers = {} 
cust_dict = {} 
for customer in doc.findall('.//Customer'): 
    cust_dict['customer_number'] = customer.findtext('CustomerNumber') 
    cust_dict['customer_first_name'] = customer.findtext('FirstName') 
    cust_dict['customer_last_name'] = customer.findtext('LastName') 
    snip snip... 
    customers[customer_number] = cust_dict # or whatever property you want to use to identify each customer, I'm assuming customer_number is some sort of id number   

webservice.close() 
return customers 

也就是说，如果你没有一类，你可以用它来创建一个Customer对象。