我想要做的是从我的数据库中获取特定值并将其解析到视图中以将其显示在表中。 我有和The model item passed into the dictionary is of type .... {Models.App} but what I passed is {Models.App, System.Double}一样的问题,并试图以类似的方式解决我的问题。在linq查询中给匿名类型键入
public Vehicle manur_name {get; set;}
public Vehicle manur_date { get; set; }
public Vehicle daily_hire_rate { get; set; }
但后来当我在LINQ查询使用它在我的控制器它给了我和错误:所以基本上我在具有模型创建的类。
var s = from veh in db.Vehicles
join c in db.VehicleCategories on veh.vehicle_category_code equals c.
join m in db.Models on veh.model_code equals m.model_code
join man in db.Manufacturers on veh.manufacturer_code equals man.manufacturer_code
where c.vehicle_category_description == cat && m.body_style == b
select new CarClass {
manur_name = man.manufacturer_name,
manur_date = m.model_code,
daily_hire_rate = veh.daily_hire_rate};
它给我的错误:
error:Cannot implicitly convert type 'decimal' to 'carRentalMVC.Models.Vehicle' Cannot implicitly convert type 'string' to 'carRentalMVC.Models.Vehicle' Cannot implicitly convert type 'string' to 'carRentalMVC.Models.Vehicle'
这是我在控制装置固定问题后:
CarRentalDatabaseDataContext db = new CarRentalDatabaseDataContext();
public ActionResult Index(String cat, String b, String sort)
{
String day_hire = "Daily hire rate";
String man_date = "Manufacturing date";
string man_n = "Manufacturer's name";
var s = db.Vehicles.Where(c => c.Model.body_style == b)
.Select(u => new CarClassViewModel {
manur_name = u.Manufacturer.manufacturer_name,
model_code = u.model_code,
daily_hire_rate = u.daily_hire_rate,
manur_date = u.manufacturing_date
})
.Distinct(); //I don't need repeating data
//this is for sorting them, but I haven't implemented this in the view yet.
if (sort == man_n){s = s.OrderBy(c=>c.manur_name);}
else if (sort == man_date){s = s.OrderBy(c =>c.manur_date);}
else if (sort == day_hire){s = s.OrderBy(c => c.daily_hire_rate);}
else{s = s.OrderBy(c => c.daily_hire_rate);}
var v = s.Select(u => new CarClassViewModel
{
manur_name = u.manur_date,
model_code = u.model_code,
daily_hire_rate = u.daily_hire_rate,
}); //this is for returning values I need
return View(v); //I've tried View(v.ToList()) as well
}
现在,这将返回我的表中的空行。这是否重要,我不解析数据的方法?
谢谢))我发现分配给变量的类型不正确。现在,我的代码中的所有东西都编译完成了,但它并没有真正返回任何东西......我应该如何解析视图? –
@NurkaKindova:很难知道你做错了什么 - 请在新问题中提供更多细节。 (你有很多的连接和过滤 - 任何一部分可能会过滤你不想要的数据。) –
好的,我修改了这个问题并添加了我目前拥有的代码。你能看看吗? –